[英]Search in php multidimensional array
我的項目中有一個分層數組,如下所示:
$Array = array(
array(
'Id' => 1,
'Title' => 'Some Text1',
'Children' => array(
array(
'Id' => 11,
'Title' => 'Some Text11',
'Children' => array(
array(
'Id' => 111,
'Title' => 'Some Text111',
),
array(
'Id' => 112,
'Title' => 'Some Text112',
'Children' => array(
array(
'Id' => 1121,
'Title' => 'Some Text1121',
)
)
)
)
),
array(
'Id' => 12,
'Title' => 'Some Text12',
'Children' => array(
array(
'Id' => 121,
'Title' => 'Some Text121',
)
)
)
)
),
array(
'Id' => 2,
'Title' => 'Some Text2',
)
);
我想在這個數組的'Title'
索引中搜索我的字符串(例如“Some Text1121”)並返回它的路徑,例如在搜索'Some Text1121'
我想返回這個結果:
"1 -> 11 -> 112 -> 1121"
或者當我搜索“Some”字符串時,返回數組中的所有路徑。 請幫助我,謝謝。
我很快給你寫了一些東西。 這並不完美,但你明白了:
<?php
function searchRec($haystack, $needle, $pathId = Array(), $pathIndex = Array()) {
foreach($haystack as $index => $item) {
// add the current path to pathId-array
$pathId[] = $item['Id'];
// add the current index to pathIndex-array
$pathIndex[] = $index;
// check if we have a match
if($item['Title'] == $needle) {
// return the match
$returnObject = new stdClass();
// the current item where we have the match
$returnObject->match = $item;
// path of Id's (1, 11, 112, 1121)
$returnObject->pathId = $pathId;
// path of indexes (0,0,1,..) - you might need this to access the item directly
$returnObject->pathIndex = $pathIndex;
return $returnObject;
}
if(isset($item['Children']) && count($item['Children']>0)) {
// if this item has children, we call the same function (recursively)
// again to search inside those children:
$result = searchRec($item['Children'], $needle, $pathId, $pathIndex);
if($result) {
// if that search was successful, return the match-object
return $result;
}
}
}
return false;
}
// useage:
$result = searchRec($Array, "Some Text11");
var_dump($result);
// use
echo implode(" -> ", $result->pathId);
// to get your desired 1 -> 11 -> 112
編輯:重寫以使函數實際返回一些東西。 它現在返回一個帶有匹配項的對象、Id 的路徑和(數組-)索引的路徑。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.