當一個字符串在另一個字符串中時，如何從DB獲取數據？

Question

我試圖從我的工作對象中獲取位置字段，但是例如當我放置location.address ，它似乎在js中語法錯誤。

這是我的常量，除了地址，城市和郵政編碼外，其他所有內容都可以正常工作。

const { title, avatar, company, postDate, jobType, payment, duration, description, address, city, postcode } = this.props.navigation.state.params; 

這是我的數據庫方案

jobs: [{
      title: {type: String},
      company: {type: String},
      avatar: {type: String},
      created: {type: Boolean},
      applied: {type: Boolean},
      description: {type: String},
      location: [{
          address: {type: String},
          postcode: {type: String},
          city: {type: String}
      }],
      jobType: {type: String},
      payment: {type: String},
      duration: {type: String},
      postDate: {type: Date},
      expDate: {type: Date}
  }]

Answer 1

location是那里的一array對象。 您必須使用一些循環來訪問它的屬性，例如

location.forEach(e=>console.log(e.address))

這可能是你的表情

const { title, avatar, company, postDate, jobType, payment, duration, description, location } = this.props.navigation.state.params; 

Answer 2

您不能在數組上點。

您的地址嵌套在數組內。

  location: [{
      address: {type: String},
      postcode: {type: String},
      city: {type: String}
  }]

要訪問它，您需要像這樣對其進行索引

jobs[0].location[0].address

Answer 3

location是一個數組。 假設每個數據的位置都是單例的，則不必數組。 更換

...
location: [{
          address: {type: String},
          postcode: {type: String},
          city: {type: String}
      }],
...

至

...
location: {
          address: {type: String},
          postcode: {type: String},
          city: {type: String}
      },
...

只需使用location.address

但它應該是一個數組，像處理數組一樣使用它

對於第一個元素

location[0].address

對於第二元素

location[1].address

對於所有元素

location.forEach(varName){
varName.address
}