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[英]how to solve The method add(double, double, int, double) in the type main is not applicable for the arguments (double, double, double, double)
[英]The method (double[]) in the type main is not applicable for the arguments (int[])
我試圖找到Java中數組的中位數。
我得到了例外:
線程“主”中的異常java.lang.Error:未解決的編譯問題:
tez3類型的中位數(double [])方法不適用於參數(int [])
在tez3.main(tez3.java:33)
我的代碼如下。 問題是什么? 如何打印雙重功能?
import java.util.Scanner;
import java.io.*;
import java.util.ArrayList;
public class tez3 {
public static void main(String args[]) throws java.io.IOException {
Scanner s = new Scanner(new File("C:\\tny\\Deneme1.txt"));
int[] numberList = new int[10];
int i = 0;
int count = 0;
int result = 0;
while (s.hasNextInt()) {
numberList[i++] = s.nextInt();
}
for (i = 0; i < numberList.length; i++) {
System.out.println(+(i + 1) + ".Value: " + numberList[i]);
}
for (i = 0; i < numberList.length; i++) {
count++;
}
for (i = 0; i < numberList.length; i++) {
result += numberList[i];
}
System.out.println("Average of the Values is: " + result / count);
System.out.println("Mode of the Values is: " + mode(numberList));
System.out.println("Median of the Values is: " + median(numberList));
}
public static int mode(int numberList[]) {
int maxValue = 0, maxCount = 0;
for (int i = 0; i < numberList.length; ++i) {
int count = 0;
for (int j = 0; j < numberList.length; ++j) {
if (numberList[j] == numberList[i]) {
++count;
}
}
if (count > maxCount) {
maxCount = count;
maxValue = numberList[i];
}
}
return maxValue;
}
public double median(double[] numberList) {
int factor = numberList.length - 1;
double[] first = new double[(double) factor / 2];
double[] last = new double[first.length];
double[] middleNumbers = new double[1];
for (int i = 0; i < first.length; i++) {
first[i] = numbersList[i];
}
for (int i = numberList.length; i > last.length; i--) {
last[i] = numbersList[i];
}
for (int i = 0; i <= numberList.length; i++) {
if (numberList[i] != first[i] || numberList[i] != last[i]) {
middleNumbers[i] = numberList[i];
}
}
if (numberList.length % 2 == 0) {
double total = middleNumbers[0] + middleNumbers[1];
return total / 2;
} else {
return middleNumbers[0];
}
}
}
問題恰恰是錯誤消息中所說的。 您的方法mean()采用double []作為參數。
但是,當您嘗試調用它時,可以給它numberList作為參數。 但是numberList是一個int [],也就是說它不是double []。
最簡單的解決方法是修改mid(),使它采用的參數是int []而不是double []。
問題是您要將int []列表中的所有元素都強制轉換為雙精度。 如果您不想將中位數的參數更改為int [],那么我處理此問題的首選方法是重載方法並轉換參數
因此,它將類似於:
public double median(int[] numberList) {
double[] doubleList = new double[numberList.size()];
for(int i=0; i<doubleList.size(); i++){
doubleList[i] = (double)numberList[i];
}
return median(doubleList);
}
如果確實更改了原始“ median”方法的參數,則每次調用它時都將強制轉換numberList元素,即
first[i] = (double) numbersList[i];
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