[英]How to insert downloaded images name into database, i dont want to insert by uploading image
我能夠讀取已經在文件夾中存在/下載的圖像名稱,但是需要在數據庫中插入,該怎么做,我不想通過上傳圖像將其插入數據庫
<?php
// to fetch images name from directory in array format
$directory = glob('C:/xampp/htdocs/mail'); // your directory
foreach (glob("*.{jpg,png,gif}", GLOB_BRACE) as $filename)
{
echo $filename;
}
$conn = mysqli_connect( $hostname, $user, $pass, $dbname );
例如:
foreach (glob("*.{jpg,png,gif}", GLOB_BRACE) as $filename)
{
$query = "INSERT INTO demo (fileName) VALUES ('$filename')";
$res = mysqli_query($conn,$query);
if($res){
echo "$filename was inserted";
}
else{
echo "$filename was not inserted";
}
}
其中,demo =表的名稱,fileName是要在其中存儲文件名稱的列。
注意:我已經使用了MySQLi Procedural。 您也可以使用MySQLi面向對象或PDO。
外部參考:
感謝您的幫助和建議...我得到了所需的輸出
$servername="Localhost";
$dbname = "email_tab";
$username="root";
$pwd="root";
// To check the established connection
$conn = new mysqli( $servername,$username,$pwd,$dbname);
if ($conn->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
//fetch images in the folder
$dir = glob('C:/xampp/htdocs/mail');
$images = glob("*.{jpg,png,gif}", GLOB_BRACE);
$filename=array(); // to assign images to array
foreach($images as $image)
{
$filename[]=$image;
}
//使用$ cnt遞增以獲取所有圖像
for($cnt=0;$cnt<=3;$cnt++)
{
$emailimage=$filename[$cnt]; // passing $cnt as to fetch all images
// insert to the database
echo $sql= "INSERT INTO email_attachment ( `ino`, `is_deleted`, `status`, `email_master_sno`, `attachment_path`, `filename`) VALUES ('1', '0', '1', '1', 'NULL', '".$emailimage."')";
$conn->query($sql);
}
echo $emailimage;
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