在PHP中使用Nominatim進行反向地理編碼

Question

我試圖在PHP中執行一些反向地理編碼。 不幸的是，我收到了一個錯誤。

$lon = 100.753;
$lat = 13.69362;

function getAddress($RG_Lat,$RG_Lon)
{
  $json = "http://nominatim.openstreetmap.org/reverse?format=json&lat=".$RG_Lat."&lon=".$RG_Lon."&zoom=27&addressdetails=1";
  $jsonfile = file_get_contents($json);
  $RG_array = json_decode($jsonfile,true);

  foreach ($RG_array as $name => $value)
  {
      if($name == "display_name")
      {
          $RG_address = $value;
          break;
      }
  }

  return $RG_address;
}

$addr = getAddress($lat,$lon);
echo "Address: ".$addr;

以下是我得到的錯誤。

<b>Warning</b>:  file_get_contents(http://nominatim.openstreetmap.org/reverse?format=json&amp;lat=13.69362&amp;lon=100.753&amp;zoom=27&amp;addressdetails=1): failed to open stream: Connection timed out in <b>/home/public_html/myapp/get_loc.php</b> on line <b>22</b><br />
<br />
<b>Warning</b>:  Invalid argument supplied for foreach() in <b>/home/public_html/myapp/get_loc.php</b> on line <b>25</b><br />
<br />
<b>Notice</b>:  Undefined variable: RG_address in <b>/home/public_html/myapp/get_loc.php</b> on line <b>34</b><br />
Address: <br />

如果我在Angular中使用下面的代碼，那么它工作正常。

showCountry($scope.latitude,$scope.longitude);
      function showCountry(lat, lon) {
              $.getJSON('//nominatim.openstreetmap.org/reverse?json_callback=?&format=json', {lat: lat, lon: lon}, function(data) {

                 console.log(data.address.town);
                 console.log('suburb- '+data.address.suburb);
                 console.log('county/district -'+data.address.county);
                 console.log('state - '+data.address.state);
                 console.log(data.address.postcode);
                  console.log(data.address.country);

             });
          }

我無法在客戶端執行此操作; 這就是我需要在php中完成它的原因。

Answer 1

您應該使用cURL （而不是file_get_contents() ）向服務器請求用戶代理標頭，因為OSM僅接受具有有效用戶代理的請求：

$lon = 100.753;
$lat = 13.69362;

function getAddress($RG_Lat,$RG_Lon)
{
  $json = "https://nominatim.openstreetmap.org/reverse?format=json&lat=".$RG_Lat."&lon=".$RG_Lon."&zoom=27&addressdetails=1";

  $ch = curl_init($json);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:59.0) Gecko/20100101 Firefox/59.0");
  $jsonfile = curl_exec($ch);
  curl_close($ch);

  $RG_array = json_decode($jsonfile,true);

  return $RG_array['display_name'];
  // $RG_array['address']['city'];
  // $RG_array['address']['country'];
}

$addr = getAddress($lat,$lon);
echo "Address: ".$addr;

輸出：

地址：短期停車場，Sky Lane，สมุทรปราการ，จังหวัดสมุทรปราการ，10520，ประเทศไทย

---

另外，正如@Kevin_Kinsey指出的那樣，您還可以將file_get_contents()與stream_context_create() ：

$opts = [
  'http' => [
    'method'=>"GET",
    'header'=>"User-Agent: Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:59.0) \r\n"
  ]
];
$context = stream_context_create($opts);
$jsonfile = file_get_contents($json, false, $context);