Python：跳過用戶輸入並稍后調用

Question

我對 Python 還很陌生，目前我只是通過制作一些在工作中使用的腳本來學習。 真的很簡單，只需要用戶輸入並將其存儲在一個字符串中以便稍后調用。 問題是是/否答案，但我希望用戶可以選擇跳過並在最后再次詢問問題，我該怎么做？

目前這就是我所擁有的：

import sys
yes = ('yes', 'y')
no = ('no', 'n')
skip = ('skip', 's')
power = str(raw_input("Does the site have power? (Yes/No): "))
if power.lower() in yes:
  pass
elif power.lower() in no:
  pass
elif power.lower() in skip:
  pass
else:
  print ''
  print '%s is an invlaid input! Please answer with Yes or No' % power
  print ''
  exit()

然后在所有問題都問完之后，在腳本的末尾，我有這個：

if power.lower() in skip:
  power = str(raw_input("Does the site have power? (Yes/No): "))
  if power.lower() in yes:
    pass
  elif power.lower() in no:
    pass
  else:
    print ''
    print '%s is an invlaid input! Please answer with Yes or No' % power
    print ''
    exit()
else:
  pass

if power.lower == 'yes':
  print 'Site has power'
else:
  print 'Site doesnt have power, NFF.'

我知道這很混亂，我只是在尋找指導/幫助。

問候，陷阱。

Answer 1

由於您對 Python 比較陌生，我會給您一些提示：

1. 將所有接收“跳過”作為響應的問題存儲到列表中。
2. 在所有問題結束時，迭代（提示：“for”循環）用戶跳過並再次詢問的所有問題。

Answer 2

# Display the sum
print('The sum of {0} and {1} is {2}'.format(num1, num2, sum))
message=("is this correct")
Print=(message)
#store input
answer = input("yes/no:")
if answer == "yes": print("thank you")
if answer == "no": print("hmm, are you sure?")
#store input
answer = input("yes/no:")
if answer == "yes" : print("please call my suppot hotline: +47 476 58 266")
if answer == "no" : print("ok goodbye:)")


if someone had a solution for line 7 when answerd yes skiped to the end desplaing ok `goodbye:) thank you`