使用Python將列表寫入CSV文件中的列

Question

我有以下清單：

theList= ["ABCD","EFGH","IJKL","MNOP"]

我想將此列表作為一行中每一列中的不同元素寫入CSV文件。 最終的CSV文件應如下所示：

  -----------------------------
1 | ABCD | EFGH | IJKL | MNOP |
  -----------------------------

我嘗試了以下代碼（使用csv庫），但是它寫入多行而不是列

tempRows = zip(theList)
    with open("Final.csv", 'w', newline='', encoding="utf8") as f:
        writer = csv.writer(f, delimiter=',')
        for tempRow in tempRows:
            writer.writerow(tempRow)

Answer 1

您是否嘗試過將參數列表直接傳遞給writerow？

writer.writerow(theList)

Answer 2

為什么要調用zip ，然后對其進行迭代？ 直接使用theList調用writerow就足夠了。

with open("Final.csv", 'w', newline='', encoding="utf8") as f:
    writer = csv.writer(f, delimiter=',')
    writer.writerow(theList)   

Answer 3

如果將每個項目放入列表中的列表中，則可以寫到單行：

theList= ["ABCD","EFGH","IJKL","MNOP"]
theList = [[string for string in theList]]
out_file = r"E:\data\one_line.csv"

with open(out_file, "w", newline="") as data:
writer = csv.writer(data)
for sub_list in theList:
    writer.writerow(sub_list)