通過對象鍵減少/過濾對象數組

Question

考慮以下對象數組

const data = [{
    name: 'James',
    sex: 'male',
  }, {
    name: 'Mike',
    sex: 'male',
  }, {
    name: 'Janet',
    sex: 'female',
  }, {
    name: 'Mary',
    sex: 'female',
}];

我想返回以下內容：

{
  males: [{
    name: 'James',
    sex: 'male',
  }, {
    name: 'Mike',
    sex: 'male',
  }]
  females: [{
    name: 'Janet',
    sex: 'female',
  }, {
    name: 'Mary',
    sex: 'female',
}]
}

我試過在數組上映射，通過鍵選擇對象，然后將它們添加到新數組中，結果是兩個數組。 從那里，我不知道如何以簡潔的方式將它們返回到新對象中。

我對ES6中的數組過濾/減少方法不太熟悉，在這里有用嗎？ 任何幫助表示贊賞！

Answer 1

您可以使用reduce

 const data = [{ name: 'James', sex: 'male', }, { name: 'Mike', sex: 'male', }, { name: 'Janet', sex: 'female', }, { name: 'Mary', sex: 'female', }]; const result = data.reduce((c, v) => { c[v.sex] = c[v.sex] || []; //Initiate if key does not exist c[v.sex].push(v); //Push the value return c; }, {}); console.log(result); 

如果您希望鍵為復數形式，則可以追加's'

const result = data.reduce((c, v) => {
  let k = v.sex + 's';
  c[k] = c[k] || [];           //Initiate if key does not exist
  c[k].push(v);                //Push the value
  return c;
}, {});

Answer 2

嘗試跟隨

 const data = [{name:'James',sex:'male',},{name:'Mike',sex:'male',},{name:'Janet',sex:'female',},{name:'Mary',sex:'female',}]; var result = data.reduce((acc, obj) => { acc[obj.sex + "s"] = acc[obj.sex + "s"] || []; acc[obj.sex + "s"].push(obj); return acc; }, {}); console.log(result); 

Answer 3

普通的舊js簡單一些-

const data = [{
    name: 'James',
    sex: 'male',
  }, {
    name: 'Mike',
    sex: 'male',
  }, {
    name: 'Janet',
    sex: 'female',
  }, {
    name: 'Mary',
    sex: 'female',
}];

var result = { males: [], females: []};
data.forEach(function(person){
  person.sex === 'male' ? result.males.push(person) : result.females.push(person);
});

console.log(result);

Answer 4

你可以做：

 const data = [{name: 'James',sex: 'male'}, {name: 'Mike',sex: 'male'}, {name: 'Janet',sex: 'female'}, {name: 'Mary',sex: 'female'}]; const result = data.reduce((a, c) => (a[c.sex + 's'].push(c), a), {males: [], females: []}); console.log(result); 

Answer 5

你回答你的問題了嗎？

const data = [{
    name: 'James',
    sex: 'male',
  }, {
    name: 'Mike',
    sex: 'male',
  }, {
    name: 'Janet',
    sex: 'female',
  }, {
    name: 'Mary',
    sex: 'female',
}];
const sex = {};
data.forEach(item => {
    if (!sex[item.sex]) sex[item.sex] = [];
    sex[item.sex].push(item);
})
console.log(sex);