使用JavaScript從AWS S3讀取JSON

Question

我有這個鏈接到AWS S3存儲桶，它會自動下載我需要的JSON。 只是為了澄清，JSON沒有顯示在網頁本身上。 我想從我目前擁有的鏈接將數據加載到JavaScript中。 我已嘗試使用下面的功能，但它沒有奏效。 該URL來自AWS-transcribe。

 function httpGetAsync(theUrl, callback) { var xmlHttp = new XMLHttpRequest(); xmlHttp.onreadystatechange = function() { if (xmlHttp.readyState == 4 && xmlHttp.status == 200) callback(xmlHttp.responseText); } xmlHttp.open("GET", theUrl, true); // true for asynchronous xmlHttp.send(null); } 

有誰知道如何從這個URL獲取JavaScript對象？

Answer 1

您可以使用新的ES6 fetch API發送HTTP請求並解析字符串化的JSON響應。

 let url = `https://s3.us-west-2.amazonaws.com/aws-transcribe-us-west-2-prod/165208660162/16/asrOutput.json?X-Amz-Security-Token=FQoDYXdzEBkaDNEU%2BEwhAVoss9PKYyK3A2qPjQJuSJOukAWY%2BTcHUY8vJoq9xQdb2%2FwEYalKy2uDvgEo03cgqeGAp%2Bjg7WGLNi4nr%2Bv5K2yOYMNG1WNmjbC8pWWArkrgGwCr8%2FXLZCxgziieoi1nV9BToNYEaSXI%2BpUR2w50o1T7a%2FY%2FQkL6hBO%2BIr3%2Fr9KYtWk%2BvC5dJryzW%2BxuHjXVv3SP%2F3SsYrqMuFLgqWct3Msvo37or4S7IxGDg6wcFzutLLQ2RrNXXa77oZJ3C%2BLn7t%2FTmthj3IJXT%2F8%2FlNEYMGc6WUG6aEqC%2F3iQmq6Pg6HDNRYQytIg0OelRhBJ7PzF0spwssUo2ZnuuRQKu%2B%2BuFbnp1Ne2B9PNDDIRRQF1bHKydwRiI%2BfIBH%2FRk3SnFH6dzppvdQjjOlZQzaVYsEE4aWJZ1UA%2FGtZlwID%2FU301m3XjdNebnH%2FgeCCrRKs1U51obmXyXeNP0veCXzgFexrf6JApN7bRrBOpWNp%2BlBXXeHI0YPa07zL62JerTwbLmSXzxbqbMSjso0t2LygCWhvsKXry5gig06%2FtyuLf%2Fxi0GRKKrDlpR2Kg%2BHGE%2B1cCbxFT3jPaIZPy1ktScZpxMw89g0kojO7W1wU%3D&X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Date=20180511T164920Z&X-Amz-SignedHeaders=host&X-Amz-Expires=900&X-Amz-Credential=ASIAJHSTNMRIX5LPMVVQ%2F20180511%2Fus-west-2%2Fs3%2Faws4_request&X-Amz-Signature=586c9c3f4a1a755757e8cd20e77fa1318cf769fce71d3167a885b209d56e537f`; let parsedObject = {}; fetch(url) .then(response => response.json()) .then(stringifiedData => parsedObject = JSON.parse(stringifiedData)) .catch(error => console.log(`Failed because: ${error}`)); console.log(parsedObject);