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[英]selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element
[英]selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element while trying to click Next button with selenium
所以我嘗試使用 selenium 單擊下一個按鈕,我嘗試使用下面的代碼,但它以錯誤結束。
元素
<input type="submit" name="submitNext" value="Next">
我的代碼
driver.find_element_by_name("submitNext").click()
但隨后它輸出這些錯誤
Traceback (most recent call last):
File "C:/Users/thomas/PycharmProjects/test/mainapp/main.py", line 194, in
<module>
visa()
File "C:/Users/thomas/PycharmProjects/test/mainapp/main.py", line 174, in visa
driver.find_element_by_name("submitNext").click()
File "C:\Users\thomas\PycharmProjects\BudgetMain\venv\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 487, in find_element_by_name
return self.find_element(by=By.NAME, value=name)
File "C:\Users\thomas\PycharmProjects\BudgetMain\venv\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 955, in find_element
'value': value})['value']
File "C:\Users\thomas\PycharmProjects\BudgetMain\venv\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 312, in execute
self.error_handler.check_response(response)
File "C:\Users\thomas\PycharmProjects\BudgetMain\venv\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 242, in check_response
raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"name","selector":"submitNext"}
(Session info: chrome=66.0.3359.170)
(Driver info: chromedriver=2.36.540470 (e522d04694c7ebea4ba8821272dbef4f9b818c91),platform=Windows NT 10.0.16299 x86_64)
任何人都對如何單擊該按鈕而不會出錯有任何想法?
這個錯誤信息...
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"name","selector":"submitNext"}
(Session info: chrome=66.0.3359.170)
(Driver info: chromedriver=2.36.540470)
...暗示ChromeDriver無法找到所需的元素。
根據您共享的 HTML 單擊元素,您可以使用以下任一定位器策略:
css_selector
:
driver.find_element_by_css_selector("input[name='submitNext'][value='Next']").click()
xpath
:
driver.find_element_by_xpath("//input[@name='submitNext' and @value='Next']").click()
但是,您的主要問題是您使用的二進制文件之間的版本兼容性如下:
支持Chrome v63-65
支持Chrome v65-67
所以ChromeDriver v2.36和Chrome Browser v66.0之間存在明顯的不匹配
@Test
。
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