R- data.table中的組的隨機樣本

Question

如何在data.table中隨機采樣例如三組，以使結果包含三組，其中原始data.table中的所有行均如此？

library(data.table)
dat <- data.table(ids=1:20, groups=sample(x=c("A","B","C", "D", "E", "F"), 20, 
replace=TRUE))

我知道如何從data.table中隨機選擇10行：

dat.sampl1 <- as.data.table(sapply(dat[], sample, 10))

還有如何按組抽樣

dat[,.SD[sample(.N, min(.N,3))], by = groups]

但是如何隨機分組？ 因此結果應如下所示：

    ids groups
     1      F
    11      F
     3      F
    18      F
     8      A
     9      A
    10      A
    17      A
    19      A
    12      E
    14      E
    16      E

Answer 1

您的意思是：

set.seed(123)
dat <- data.table(ids=1:20, groups=sample(x=c("A","B","C", "D", "E", "F"), 20, 
replace=TRUE))
dat[groups %in% sample(unique(dat[, groups]), size = 3)][order(groups)]
#     ids groups
#  1:   3      C
#  2:  10      C
#  3:  12      C
#  4:   7      D
#  5:   9      D
#  6:  14      D
#  7:   4      F
#  8:   5      F
#  9:   8      F
# 10:  11      F
# 11:  16      F
# 12:  20      F

如果要對具有replacement的組進行抽樣，則可以執行以下操作，其中對A進行了兩次抽樣：

dat[unique(dat[, list(groups)])[sample(.N, 3, replace = TRUE)], on = "groups"]
#    ids groups
# 1:   3      C
# 2:  10      C
# 3:  12      C
# 4:   6      A
# 5:  15      A
# 6:  18      A
# 7:   6      A
# 8:  15      A
# 9:  18      A

Answer 2

此代碼有效，使用單行基礎R代碼（使用%in%檢查使用sample函數生成的索引：

df1[df1[,'groups'] %in% sample(unique(df1[,'groups']), size = 3, replace = F), ]

例如：

> df1 <- data.frame("ids" = 1:20, "groups" = sample(LETTERS[1:4], size = 20, replace = T))
> df2 <- df1[df1[,'groups'] %in% sample(unique(df1[,'groups']), size = 3, replace = F), ]
> df2[order(df2[,'groups']),]
   ids groups
4    4      B
6    6      B
18  18      B
20  20      B
1    1      C
2    2      C
3    3      C
9    9      C
12  12      C
16  16      C
19  19      C
7    7      D
11  11      D