使python函數輸入列表

Question

我正在為一個函數編寫代碼，並想打開此輸入，

[], [], ["pepperoni", "pepperoni"], wings=[10, 20], drinks=["small"]

在一個函數cost_calculator中

問題在於它不讓我接受，因為其中有翅膀和飲料一詞。 嘗試將其轉換為列表會給我錯誤的語法。 我也無法從輸入中刪除“翅膀和飲料”一詞。 我的代碼：

def cost_calculator(x):
    cost=0
    drinks={"small":2.00,"medium":3.00,"large":3.50,"tub":3.75}
    wings={10:5.00,20:9.00,40:17.50,100:48.00}
    toppings={"pepperoni":1.00,"mushroom":0.50,"olive":0.50,"anchovy":2.00, "ham":1.50}
 pizza={[]:13.00}
 for i in x:
        if i in pizza:
            cost=cost+pizza[i]
        elif i in toppings:
            cost=cost+toppings[i]
        elif i in drinks:
            cost=cost+drinks[i]
        elif i in wings:
            cost=cost+wings[i]
        else:
            break
  return cost

輸入時

cost_calculator([], [], ["pepperoni", "pepperoni"], wings=[10, 20], drinks=["small"])

它給我

cost_calculator() got an unexpected keyword argument 'wings'

我需要使用[]來顯示比薩的價值，

cost=cost+13.00

我該如何克服

Answer 1

不能完全確定函數的參數是什么，但是如果要使用關鍵字args，請使用 **語法：

所以，我想我知道args可以是什么（按此順序）：

• 任意數量的[] ，每個代表一個披薩
• 一份澆頭清單（顯然這是可選的）
• 可選的命名列表（機翼，飲料）

因此，我們可以使用可變數量的args和關鍵字args ：

# Tuple of var args and a dictionary of keyword args
def cost_calculator(*args, **kwargs):
    drinks = {"small": 2.00, "medium": 3.00, "large": 3.50, "tub": 3.75}
    wings = {10: 5.00, 20: 9.00, 40: 17.50, 100: 48.00}
    toppings = {"pepperoni": 1.00, "mushroom": 0.50, "olive": 0.50, "anchovy": 2.00, "ham": 1.50}

    cost = 0
    coupon_value = 0.0

    # args is a tuple of unnamed parameters
    for a in args:
        # [] has 0 length so it's a pizza
        if 0 == len(a):
            cost += 13.00
        # Otherwise it must be toppings
        else:
            cost += sum([toppings[x] for x in a if x in toppings])

    # Step through the keyword args
    for key,value in kwargs.items():
        if key == "drinks":
            cost += sum([drinks[x] for x in value if x in drinks])
        elif key == "wings":
            cost += sum([wings[x] for x in value if x in wings])
        elif key == "coupon":
            coupon_value = value
        else:
            break
    return cost * (1.0 - coupon_value)

c = cost_calculator([], [], ["pepperoni", "pepperoni"], wings=[10,10], drinks=["small"], coupon=0.1)
print(c)