從十六進制到ASCII中的ASCII

Question

嘿，我全部寫了這個腳本：

import re

arrayofhex =[]
hexedarr=[]
string_input = raw_input()
key = "0x3c"
encodehex = string_input.encode("hex")

hexsplit = re.findall('..?', encodehex)


for letter in hexsplit:
     a = hex(int(letter,16))
     arrayofhex.append(a)

print arrayofhex

print "Xoring with Key 0x3c turns to:"

for hexedletter in arrayofhex:

    xor = hex(int(hexedletter,16) ^ int(key,16))
    hexedarr.append(xor)

print hexedarr

如您所見，用戶可以插入一些字符串，然后代碼將其設置為十六進制，然后使用0x3c的密鑰對其進行異或，我想獲取異或過程的ascii有人可以幫助嗎？

Answer 1

好吧，所以我進行了一些更改並使它可以在這里工作，這是一個很好的完整腳本！！

import re

Array_of_hex =[]
Hexed_array=[]
Xord_array=[]

string_input = raw_input()
key = "0x3c"

Encode_to_hex = string_input.encode("hex")

Hex_split = re.findall('..?', Encode_to_hex)


for letter in Hex_split:
     a = hex(int(letter,16))
     Array_of_hex.append(a)

print Array_of_hex

print "Xoring with Key 0x3c turns to:"

for hexedletter in Array_of_hex:

    xor = hex(int(hexedletter,16) ^ int(key,16))
    Hexed_array.append(xor)

print Hexed_array


for hextoascii_letter in Hexed_array:
    toascii = chr(int(hextoascii_letter,16))
    Xord_array.append(toascii)


xord_string = "".join(Xord_array)
print "Xored Ascii:"
print xord_string