[英]undeclared php variable in contact form
我在使用簡單的聯系表時遇到問題。
我得到的錯誤是:
注意:未定義索引:第 29 行 contact.php 中的術語
注意力! 您必須選中隱私政策框才能接受我們的條款。
代碼:
if (!defined("PHP_EOL")) define("PHP_EOL", "\r\n");
$name = $_POST['name'];
$email = $_POST['email'];
$comments = $_POST['comments'];
$terms = $_POST['terms']; // <---- line 29
if(trim($terms) == '') {
echo '<div class="alert error"><div class="msg">Attention! You have to check
the Privacy Policy box to accept our terms.</div></div>';
exit();
}
if(trim($comments) == '') {
echo '<div class="alert error"><div class="msg">Attention! Please enter your
message.</div></div>';
exit();
}
if(get_magic_quotes_gpc()) {
$comments = stripslashes($comments);
}
模板文件如下:
<form action="<?php echo $this->config->get('config_url').'ajax/contact.php' ?>" method="post" id="contact_form" enctype="multipart/form-data">
<table>
<tr>
<td>
<label for="name"><?php echo $entry_name; ?></label>
<input type="text" name="name" id="name" style="margin-right:20px" value="<?php echo $name; ?>" />
<?php if ($error_name) { ?>
<span class="error"><?php echo $error_name; ?></span>
<?php } ?>
</td>
<td>
<label for="email"><?php echo $entry_email; ?></label>
<input type="text" name="email" id="email" value="<?php echo $email; ?>" />
<?php if ($error_email) { ?>
<span class="error"><?php echo $error_email; ?></span>
<?php } ?>
</td>
</tr>
</table>
<label for="enquiry"><?php echo $entry_enquiry; ?></label>
<textarea name="enquiry" id="enquiry" cols="30" rows="5"><?php echo $enquiry; ?></textarea>
<?php if ($error_enquiry) { ?>
<span class="error"><?php echo $error_enquiry; ?></span>
<?php } ?>
<input type="checkbox" name="terms" value="<?php echo $terms; ?>" />
<label for="terms">Tick this box to confirm you comply with our <a href="/privacy-policy/">Privacy Terms</a></label>
<input type="submit" id="submit" value="<?php echo $button_continue; ?>" class="button dark-bt" />
</form>
試試這個:
$terms = isset($_POST['terms']) ? $_POST['terms'] : '';
只有當用戶在表單中選中它時,您才會獲得復選框字段。
所以,總是像這樣檢查復選框和單選按鈕。
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