按對象數組過濾對象數組[TypeScript] [ES6]

Question

如何通過帶有條件的對象數組過濾對象數組。

接口：

interface Person {
    age: number;
    available: boolean;
}

interface PersonFilter {
    predicateFn(arg: Person): boolean;
}

數據：

const persons = [
  {
    "age": 2,
    "available": false
  },
  {
    "age": 5,
    "available": true
  }
];

過濾條件：

const filters = [
    {predicateFn: person => person.available},
    {predicateFn: people => person.age > 2}
];

如何使用當前過濾器結構過濾此對象數組？

function getFilteredPersons(filters): Person[]{
return persons.filter( ?? );
}    

預期產量：

  [
      {
        "age": 5,
        "available": true
      }
    ]

Answer 1

您可以使用Array.prototype.every函數來嘗試它，就像這樣：

 const persons = [{ age: 2, available: false }, { age: 5, available: true } ]; const filters = [{ predicateFn: person => person.available }, { predicateFn: person => person.age > 2 } ]; function getFilteredPersons(filters) { return persons.filter(p => filters.every(filter => filter.predicateFn(p))); } console.log(getFilteredPersons(filters));