無法使用多個LEFT JOIN提取數據

Question

我需要提取匹配到特定日期的所有國家/地區，表格結構是這樣的：

TABLE NAME  |  FIELDS
country     | id, name  
round       | id, season_id
season      | id, competition_id
competition | id, country_id
match       | id, round_id, date

單個match記錄具有以下組成：

id: 60856
round_id: 65
date: 2018-06-02 00:00:00

如您所見，我在match有爭議的地方有round_id 。 round上的設計如下：

id: 65
season_id: 280

season代表round的容器，因此season記錄具有以下結構：

id: 161
competition_id: 48

一個season的competition包含了所有的rounds 。 competition記錄包含以下country ：

id: 48
coutry_id: 2

最后是country ：

id: 2
name: albania

如何提取今天有比賽的所有國家/地區？

這是我嘗試的：

$app->get('/country/get_countries/{date}', function (Request $request, Response $response, array $args)
{
    $sql = $this->db->query("SELECT * FROM country
      LEFT JOIN `match` ON round_id = round.id
      LEFT JOIN round ON season_id = season.id
      LEFT JOIN season ON competition_id = competition.id
      WHERE match.datetime = " . $args["date"] . "");

    $sql->execute();
    $countries = $sql->fetchAll();
    return $response->withJson($countries);
});

這將返回：

SQLSTATE [42S22]：找不到列：1054“ on子句”中的未知列“ round.id”

更新：

  $sql = $this->db->query("SELECT * FROM country
  LEFT JOIN competition ON country_id = competition.country_id
  LEFT JOIN competition_seasons ON competition_id = competition.id
  LEFT JOIN competition_rounds ON competition_rounds.season_id = competition_seasons.id
  LEFT JOIN `match` ON match.round_id = competition_rounds.id
  WHERE match.datetime = " . $args["date"] . "");

Answer 1

SELECT * FROM country
      LEFT JOIN competition ON country.id = competition.country_id
      LEFT JOIN season ON season.competition_id= competition.id
      LEFT JOIN round ON round.season_id= season.id
      LEFT JOIN match ON match.round_id= round.id
      WHERE match.datetime = " . $args["date"] . ""