用 Python 自動化無聊的東西 - 逗號代碼

Question

所以我想出了一個有效的解決方案，它不使用牛津逗號，有點麻煩，有沒有更干凈的方法來做到這一點？

def stringy(spam):
    output = ""
    for thing in spam[:-1]: 
        output = output + thing + ", "
    output = output[:-2] + " and " + spam[-1] #removes the last 2 chars 
    return output

spam = ['cats','cats','cats','cats', 'apples', 'bananas', 'tofu', 'cats']

print(stringy(spam))`

Answer 1

def list1(name):
    name = name.insert(len(name)-1, 'and')
    for i in range(len(spam)-2):

        print(spam[i] ,end=', ' )
    print(spam[-2], end=' ')    
    print(spam[-1],end='')



spam = ['apples', 'bananas', 'tofu', 'cats' , 'hello']
list1(spam)

Answer 2

嘗試以下操作：-

def stringy(spam):
    if len(spam) < 2:
        return ' and '.join(spam)
    else:
        return ', '.join(spam[:-1]) + ' and '+spam[-1]

spams = [['cats','cats','cats','cats', 'apples', 'bananas', 'tofu', 'cats'],['tofu', 'cats'],[]]

for spam in spams:
    print(stringy(spam))

Answer 3

這本質上是@Azat Ibrakov 在單行中所擁有的，我只是在 python 中針對字符串操作警告againts + 。

def commanize(spam: list):
    if len(spam) >= 2:
        comma_str = ', '.join(spam[:-1])
        return ' and '.join([comma_str, spam[-1]])
    else:
        return spam[0]

assert commanize(['a', 'b', 'c'])  == 'a, b and c'
assert commanize(['a', 'b'])  == 'a and b'
assert commanize(['a'])  == 'a'

Answer 4

我的回答和第一篇文章！

def returnString(list):
    length = len(list)
    i = 0
    outputstring = list[i]
    i += 1
    while i < length - 1:
        outputstring = outputstring + ', '+ str(list[i])
        i = i + 1
outputstring = outputstring + ' and ' + list[i]
print(outputstring)

list = ['Ants', 'Spiders', 'Rabbits', 'Leopards', 'Lions', 'Tigers', 'Elephants']
returnString(list)

Answer 5

試試這個

", ".join(spam[:-1]) + " and " + spam[-1] if len(spam)>1 else spam[-1] if len(spam)>=1 else ""