UIDatePicker返回當前日期未選擇的日期

Question

我有一個UIDatePicker ，它按照下面的代碼打印選定的日期。 但是，它不打印所選日期，僅顯示當前日期。

@objc func setupDiscoverButton() {

    let cell = Bundle.main.loadNibNamed("FirstTableViewCell", owner: self, options: nil)?.first as! FirstTableViewCell

    // Date
    let sessionDate = cell.datePicker.date

    print("date: \(sessionDate)")
}

這是我為UIDatePicker定義的地方。

 func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

    let cell = Bundle.main.loadNibNamed("FirstTableViewCell", owner: self, options: nil)?.first as! FirstTableViewCell

    // Date & time picker
    cell.datePicker.minimumDate = Date()
    cell.datePicker.timeZone = TimeZone.current

    // Discover button
    cell.discoverButton.addTarget(self, action: #selector(setupDiscoverButton), for: .touchUpInside)

    return cell
}

Answer 1

要獲取DatePicker的更改，請收聽datePickerChanged

datePicker.addTarget(self, action: #selector(datePickerChanged(picker:)), for: .valueChanged)

所以你的細胞會

 func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

    let cell = Bundle.main.loadNibNamed("FirstTableViewCell", owner: self, options: nil)?.first as! FirstTableViewCell

    // Date & time picker
    cell.datePicker.minimumDate = Date()
    cell.datePicker.timeZone = TimeZone.current
cell.datePicker.addTarget(self, action: #selector(datePickerChanged(picker:)), for: .valueChanged)

    // Discover button
    cell.discoverButton.addTarget(self, action: #selector(setupDiscoverButton), for: .touchUpInside)

    return cell
}

  @objc func datePickerChanged(picker: UIDatePicker) {
        print(picker.date)
    }