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[英]Jena: How to get Integer result from SPARQL (Jena) ResultSet in Java?
[英]SHACL with Jena, how to get the Model after SPARQL CONSTRUCT from the shape?
我有這個數據文件:
@prefix ex: <http://example.com/ns#> .
ex:John
a ex:Person ;
a ex:parent ;
a ex:male .
和這個形狀文件:
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
@prefix sh: <http://www.w3.org/ns/shacl#> .
@prefix xsd: <http://www.w3.org/2001/XMLSchema#> .
@prefix ex: <http://example.com/ns#> .
ex:RuleOrderExampleShape
a sh:NodeShape ;
sh:targetClass ex:Person ;
sh:rule [
a sh:SPARQLRule;
rdfs:label "Construct a father if someone is a parent and a male";
sh:prefixes ex: ;
sh:construct """
CONSTRUCT {
$this a ex:uncle .
}
WHERE {
$this a ex:parent .
$this a ex:male .
}
"""
] .
我的代碼當前為:
Model dataModel = ModelFactory.createDefaultModel();
dataModel.read(data);
Model shapeModel = ModelFactory.createDefaultModel();
shapeModel.read(shape);
Resource reportResource = ValidationUtil.validateModel(dataModel, shapeModel, true);
如何獲得將包含新三元組的模型(例如:約翰a父親:父親)?
假設您已將SHACL的依賴項包含在pom.xml中
<dependency>
<groupId>org.topbraid</groupId>
<artifactId>shacl</artifactId>
<version>1.0.1</version>
</dependency>
您可以使用以下代碼:
Model shapeModel = JenaUtil.createDefaultModel();
shapeModel.read(strShapeFile);
Model inferenceModel = JenaUtil.createDefaultModel();
inferenceModel = RuleUtil.executeRules(infModel, shapeModel, inferenceModel, null);
inferenceModel
將包含新的三元組。
我也在我的博客上寫過這個。 請參閱例如SHACL規則執行 ,在這里您可以找到完整的代碼示例。
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