[英]Get the argument passed to mock_open and call a different function for mock
[英]Mock function to return different value based on argument passed
在我的測試函數中,我的模擬行為不正常,因為當我mock
我的get_config
函數時,我只知道如何模擬它以返回一個值。 如何在我的mock
中添加一些邏輯,以便模擬僅在get_config
傳遞"restricted"
參數時返回不同的值
def func():
conf1 = get_config("conf1")
conf2 = get_config("conf2")
conf3 = get_config("conf3")
restricted_datasets = get_config("restricted")
dataset = get_config("dataset")
if dataset not in restricted_datas:
return run_code()
您可以按照官方文檔中的說明將函數分配給side_effect
from unittest.mock import Mock
def side_effect(value):
return value
m = Mock(side_effect=side_effect)
m('restricted')
'restricted'
class Ctx():
def get_config(confName):
return confName
def mock_get_config(value):
if value == "conf1":
return "confA"
elif value == "conf2":
return "confB"
else:
return "UnknownValue"
class CtxSourceFileTrial(unittest.TestCase):
def test(self):
mockCtx = Mock()
mockCtx.get_config.side_effect = mock_get_config
self.assertEqual("confA", mockCtx.get_config("conf1"))
self.assertEqual("confB", mockCtx.get_config("conf2"))
#
# By the way I think Python is EXTREMELY screwy, Adligo
#
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