[英]Batch script to find and replace 2 different strings at once
我有一個類似此示例的XML文件:
<fruit>
<desc>xxx / yyy / zzz</desc>
</fruit>
<fruit>
<desc></desc>
</fruit>
<fruit>
<desc>abc / def / ghi</desc>
</fruit>
我正在使用批處理腳本來修復節點“ desc”。 這是修復后的結果:
<fruit>
<desc>xxx/yyy/zzz</desc>
</fruit>
<fruit>
<desc>N/A</desc>
</fruit>
<fruit>
<desc>abc/def/ghi</desc>
</fruit>
如何替換2個不同的字符串而不掃描所有文件兩次? 這是腳本:
@echo off
setlocal enabledelayedexpansion
set "input_xml=xmlfile.xml"
set "search=^<desc^>^</desc^>"
set "search2= / "
set "replace=^<desc^>N/A^</desc^>"
set "replace2=/"
for /f "delims=" %%i in ('type "!input_xml!" ^& break ^> "!input_xml!" ') do (
set FixNullNode=%%i
echo !FixNullNode:%search%=%replace%! >>"!input_xml!"
)
for /f "delims=" %%v in ('type "!input_xml!" ^& break ^> "!input_xml!" ') do (
set FixSpaceSlash=%%v
echo !FixSpaceSlash:%search2%=%replace2%! >>"!input_xml!"
)
pause
謝謝
只需將第二個替換項移入第一個for命令中即可。
@echo off
setlocal enabledelayedexpansion
set "input_xml=xmlfile.xml"
set "search=^<desc^>^</desc^>"
set "search2= / "
set "replace=^<desc^>N/A^</desc^>"
set "replace2=/"
for /f "delims=" %%i in ('type "!input_xml!" ^& break ^> "!input_xml!" ') do (
set "Fix=%%i"
set "Fix=!Fix:%search%=%replace%!"
echo !Fix:%search2%=%replace2%! >>"!input_xml!"
)
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