[英]How can i echo image size in PHP?
我嘗試將圖像大小放入圖像src標記中,但仍然無法正常工作。 圖像可以很好地顯示。
<?php
$files = glob("uploads/*.*");
echo "<table border =\"1\" style='border-collapse: collapse'>";
for ($row=1; $row <= 4; $row++) {
echo "<tr> \n";
for ($col=1; $col<=4; $col++) {
$f=$f+1;
$getfile = $files[$f];
echo "<td>";
echo "<img src=$getfile > ";
echo "</td>";
}
echo "</tr>";
}
echo "</table>";
您可以使用getimagesize()函數http://php.net/manual/en/function.getimagesize.php來獲取圖像大小
<?php
$files = glob("uploads/*.*");
echo "<table border =\"1\" style='border-collapse: collapse'>";
for ($row=1; $row <= 4; $row++) {
echo "<tr> \n";
for ($col=1; $col<=4; $col++) {
$f=$f+1;
$getfile = $files[$f];
$size = getimagesize($getfile);
echo "<td>";
echo "<img src=$getfile $size[3]> ";
echo "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
PHP Function文件大小將在這里幫助您
echo filesize($filename) . ' bytes';
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