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[英]How to fetch the latest status from a table of Updates and join it with table of details in MySQL?
[英]How do I fetch the latest status of each id from table?
請考慮下表:
mysql> desc foo;
+------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(255) | NO | | NULL | |
| created_at | datetime | NO | | NULL | |
| updated_at | datetime | NO | | NULL | |
+------------+--------------+------+-----+---------+----------------+
4 rows in set (0.00 sec)
mysql> desc bar;
+-----------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| foo_id | int(11) | NO | MUL | NULL | |
| status | varchar(255) | YES | | NULL | |
| created_at | datetime | NO | | NULL | |
| updated_at | datetime | NO | | NULL | |
+-----------------+--------------+------+-----+---------+----------------+
5 rows in set (0.01 sec)
我想從條形表中獲取最近更新的foo_id和狀態,並且foo_id也包含多個狀態
我嘗試了以下查詢:
SELECT foo_id, status
FROM bar d1
WHERE d1.updated_at =
(SELECT MAX(d2.updated_at)
FROM bar d2
WHERE d1.foo_id = d2.foo_id)
GROUP BY foo_id
ORDER BY updated_at DESC;
在其他計算機上收到以下錯誤:
未處理的拒絕SequelizeDatabaseError:SELECT列表的表達式#2不在GROUP BY子句中,並且包含未聚合的列'dev.d1.status',該列在功能上不依賴於GROUP BY子句中的列; 這與sql_mode = only_full_group_by不兼容
如何從條形表中獲取每個foo_id的最新狀態?
如果您只想要最大updated_at的ID,則可以使用
select foo_id, status
from bar
where updated_at = (
select MAX(updated_at)
from bar
)
或使用聯接
select foo_id, status
from bar
INNER JOIN (
select MAX(updated_at) max_date
from bar
) t on t.max_date = bar.updated_at
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