在找到的下一行價值中獲取文本

Question

我有以下名為people.txt文本文件，其內容如下：

mikey.mcgurk
Boss Man

michelle.mcgurk
Boss Man 2

我想調整我的PHP腳本以獲取每個用戶名mikey.mcgurk的行中的數據，因此，如果我搜索mikey.mcgurk ，我的腳本將輸出Boss Man 。

PHP：

<?php //
$file = 'people.txt';
$searchfor = "mikey.mcgurk";

// the following line prevents the browser from parsing this as HTML.
header('Content-Type: text/plain');

// get the file contents, assuming the file to be readable (and exist)
$contents = file_get_contents($file);
// escape special characters in the query
$pattern = preg_quote($searchfor, '/');
// finalise the regular expression, matching the whole line
$pattern = "/^.*$pattern.*\$/m";
// search, and store all matching occurences in $matches
if(preg_match_all($pattern, $contents, $matches)){
   // write all of this to a text file
   echo implode("\n", $matches[0]);
}
else{
   echo "No matches found";
}

Answer 1

你可以這樣

$contents = file_get_contents($file);

$contents = explode(PHP_EOL, $contents);

if(array_search($searchfor, $contents) !== false){
    echo $contents[array_search($searchfor, $contents)+1];
}

Answer 2

您可以像這樣比較：

$contents = file_get_contents($file);
$lines = explode("\n",$contents);
for($i = 0; $i < count($lines); $i++) {
    if( $lines[$i] ==$searchfor ) {
        echo "Username ".$lines[$i+1];
    }
}

Answer 3

您可以通過獲取數組中的所有行來代替使用正則表達式

$lines = explode(PHP_EOL, $contents);

然后得到結果的關鍵

$keys = array_keys($lines, $pattern);

並將鍵增加1以得到下一行

foreach ($keys as $key) { echo $lines[++$key]; }