如何用Laravel術語編寫PHP SQL查詢

Question

我將如何用laravel的術語編寫此php mysql查詢。 我已經檢查了文檔，但在Laravel 4.2中找不到有關SQL的IF或AS

這是php查詢：

query("SELECT IF(friends.sender = ".$_SESSION["user"].", friends.recipient, friends.sender) AS user_id FROM friends WHERE friends.status=1 AND friends.sender = ".$_SESSION["user"]." OR friends.recipient = ".$_SESSION["user"]." AND friends.status=1 ")

我正在嘗試像這樣格式化

@foreach(Friends::if("sender","=",Auth::user()->id)->as("user_id")->where("status","=",1)->where("sender","=",Auth::user()->id)->orWhere("recipient","=",Auth::user()->id)->where()->get() as $user_friends)

Answer 1

您可以使用查詢構建器或Eloquent來做到這一點

與雄辯（此代碼將被添加到控制器）

public function getFriends($arg1, $arg2)
{
  $friends = Frind::where('filed-name', 'operator', $arg1)->where('filed-name', 'operator', $arg2)->all();
  return view('/view-name', ['friends' => $friends];
}

或使用查詢生成器

public function getFriends($arg1, $arg2)
{
  $friends = DB::table('friends')->select('friends.*')->where('filed-name', 'operator', $arg1)->where('filed-name', 'operator', $arg2)->get();
  return view('/view-name', ['friends' => $friends];
}

您可以在此處和Eloquent上閱讀有關查詢構建器的更多信息 。