如何使用php將多個表記錄從json導入到mysql

Question

我有來自多個表多條記錄的json文件。 json文件是從本地mysql數據庫創建的，我還有另一個具有相同架構的在線數據庫。 但是每個表都沒有相同數量的字段和相同的數據/值。 但是所有表的某些字段名稱都是相同的（id，add_on，last_updated）。 我想通過執行單個php文件將這些json文件值導入在線數據庫。

json文件如下所示：

[
    {
        "tableName":"table_Name_1",
        "rows":[
                {   
                    "t1column1":"valuet1row11",
                    "t1column2":"valuet1row12",
                    "t1columnx":"valuet1row1x"
                },
                {   
                    "t1column1":"valuet1row21",
                    "t1column2":"valuet1row21",
                    "t1columnx":"valuet1row2x"  
                },
                {   
                    "t1column1":"valuet1rowx1",
                    "t1column2":"valuet1rowx2",
                    "t1columnx":"valuet1rowxx"  
                }
               ]
    },
        {
        "tableName":"table_Name_2",
        "rows":[
                {   
                    "t2column1":"valuet2row11",
                    "t2column2":"valuet2row12",
                    "t2columnx":"valuet2row1x"
                },
                {   
                    "t2column1":"valuet2row21",
                    "t2column2":"valuet2row22",
                    "t2columnx":"valuet2row2x"  
                },
                {   
                    "t2column1":"valuet2rowx1",
                    "t2column2":"valuet2rowx2",
                    "t2columnx":"valuet2rowxx"
                }
               ]
    },
        {
        "tableName":"table_Name_n",
        "rows":[
                {   
                    "tncolumn1":"valuetnrow11",
                    "tncolumn2":"valuetnrow12",
                    "tncolumnx":"valuetnrow1x"
                },
                {   
                    "tncolumn1":"valuetnrow21",
                    "tncolumn2":"valuetnrow22",
                    "tncolumnx":"valuetnrow2x"  
                },{ 
                    "tncolumn1":"valuetnrowx1",
                    "tncolumn2":"valuetnrowx2",
                    "tncolumnx":"valuetnrowxx"
                }
               ]
    },
]

以下php代碼用於將json文件記錄導入數據庫中的單個表中。 （這里的single_table.json僅包含單個表記錄）

<?php
    try
    {
        $connect = mysqli_connect("localhost", "fmart", "password", "mart_dbsync");    
        $query = '';
        $table_data = '';
        $filename = "single_table.json";

        $data = file_get_contents($filename);
        $array = json_decode($data, true); 

        foreach($array as $row) 
        {
            $query .= "INSERT INTO purchases(id, invoicenum, supplier, stock_keeper, counter, added_by, is_deleted, description, is_opening_stock, department, added_on, last_updated) VALUES ('".$row["id"]."', '".$row["invoicenum"]."', '".$row["supplier"]."', '".$row["stock_keeper"]."', '".$row["counter"]."', '".$row["added_by"]."', '".$row["is_deleted"]."', '".$row["description"]."', '".$row["is_opening_stock"]."', '".$row["department"]."', '".$row["added_on"]."', '".$row["last_updated"]."') ON DUPLICATE KEY UPDATE invoicenum='".$row["invoicenum"]."', supplier='".$row["supplier"]."', stock_keeper='".$row["stock_keeper"]."', counter='".$row["counter"]."', added_by='".$row["added_by"]."', is_deleted='".$row["is_deleted"]."', description='".$row["description"]."', is_opening_stock='".$row["is_opening_stock"]."', department='".$row["department"]."', added_on='".$row["added_on"]."', last_updated='".$row["last_updated"]."';";
        }

            mysqli_multi_query($connect, $query);  

            echo "<h1>All purchases appended </h1>";
    } 

    catch(Exception $e)
    {   
        echo $e->getMessage();    
    }
?>

在上面的php代碼中，表名在INSERT語句中進行了硬編碼。 但是通過使用新的json（如上面的json格式），它包含25個以上的表，並且表名應從json文件中獲取。

這是回顯的結果：

contacts

Insert query:

INSERT INTO contacts 
(First_Name, Last_Name, Company, Business_Phone, Email_Address)
VALUES
('Dave','Frank','Company1','0115 999999','zvv@zz.com'),
('Dave','Blogs','Company2','0115 888888','zvv@zz.com'),
('David','frank','Company3','0115 777777','zvv@zz.com')

Error: 1
INSERT INTO contacts (First_Name, Last_Name, Company, Business_Phone, Email_Address) VALUES ('Dave','Frank','Company1','0115 999999','zvv@zz.com'), ('Dave','Blogs','Company2','0115 888888','zvv@zz.com'), ('David','frank','Company3','0115 777777','zvv@zz.com')
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1contacts_old

Insert query:

INSERT INTO contacts_old 
(First_Name, Last_Name, Company, Business_Phone, Email_Address)
VALUES
('Dave','Frank','Company1','0115 999999','zvv@zz.com'),
('Dave','Blogs','Company2','0115 888888','zvv@zz.com'),
('David','frank','Company3','0115 777777','zvv@zz.com')

Error: 1
INSERT INTO contacts_old (First_Name, Last_Name, Company, Business_Phone, Email_Address) VALUES ('Dave','Frank','Company1','0115 999999','zvv@zz.com'), ('Dave','Blogs','Company2','0115 888888','zvv@zz.com'), ('David','frank','Company3','0115 777777','zvv@zz.com')
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1

Answer 1

這只是一個框架，展示了基於JSON中的數據構建查詢的想法。 這將需要根據您的實際數據和表模式進行一些調整和調整。

作為改進，我還將為每個表構建一個具有多個值的INSERT。

編輯

更改了代碼以讀取所有表並將其插入JSON文件。 假定JSON文件中的表名和列名與實際表匹配。 它還為具有id列的表添加ON DUPLICATE KEY UPDATE。

注意：未經測試，可能有錯別字。

<?php
    try
    {
        $connect = mysqli_connect("localhost", "fmart", "password", "mart_dbsync"); 
        $query = '';
        $table_data = '';
        $filename = "single_table.json";

        $data = file_get_contents($filename);
        $array = json_decode($data, true); 

        foreach($array as $set) 
        {
            $tblName = $set['tableName'];
            if(sizeof($set['rows']) > 0) {
                $query = '';
                $colList = array();
                $valList = array();
                //  Get list of column names
                foreach($set['rows'][0] as $colname => $dataval) {
                    $colList[] = "`".$colName."`";
                }
                $query .= "INSERT INTO `".$tblName."` \n";
                $query .= "(".implode(",",$colList).")\nVALUES\n";
                //  Go through the rows for this table.
                foreach($set['rows'] as $idx => $row) {
                    $colDataA = array();
                    //  Get the data values for this row.
                    foreach($row as $colName => $colData) {
                        $colDataA[] = "'".$colData."'";
                    }
                    $valList[] = "(".implode(",",$colDataA).")";
                }
                //  Add values to the query.
                $query .= implode(",\n",$valList)."\n";
                //  If id column present, add ON DUPLICATE KEY UPDATE clause
                if(in_array("`id`",$colList)) {
                    $query .= "ON DUPLICATE KEY UPDATE\n\tSet ";
                    $tmp = array();
                    foreach($colList as $idx => $colName) {
                        $tmp[] = $colName." = new.".$colname." ";
                    }
                    $query .= implode(",",$tmp)."\n";
                } else {
                    echo "<p><b>`id`</b> column not found. <i>ON DUPLICATE KEY UPDATE</i> clause <b>NOT</b> added.</p>\n";
                    echo "<p>Columns Found:<pre>".print_r($colList,true)."</pre></p>\n";
                }
                echo "<p>Insert query:<pre>$query</pre></p>";
                $r = mysqli_query($connect, $query);  
                echo "<h1>".mysqli_num_rows($r)." Rows appeded in $tblName</h1>";
            } else {
                echo "<p>No rows to insert for $tblName</p>";
            }
        }
    } 

    catch(Exception $e)
    {   
        echo $e->getMessage();  
    }
?>