由寫入另一張表的行中的多列進行分區

Question

假設我有這張桌子：

+------+-------+-------+-------+-------+--------+
| User | Value | Rule1 | Rule2 | Rule3 | Rule4  |
+------+-------+-------+-------+-------+--------+
|    1 |    10 |    20 |    14 |    15 |     22 |
|    2 |     5 |    20 |     7 |     8 |     25 |
+------+-------+-------+-------+-------+--------+

我想通過查詢來做一個分區，像這樣：

SELECT sum(Value) OVER (PARTITION BY Rule1, Rule2)
FROM MY_TABLE

但我不想寫“ Rule1，Rule2”。 我想讀一張像

+----+-------+
| ID | Rules |
+----+-------+
|  1 | Rule1 |
|  1 | Rule2 |
|  2 | Rule1 |
|  2 | Rule2 |
|  2 | Rule3 |
|  3 | Rule2 |
|  3 | Rule3 |
|  3 | Rule4 |
+----+-------+

所以我可以這樣寫：

SELECT sum(Value) OVER (PARTITION BY "all rules separated by comma where ID = 1")
FROM MY_TABLE

可能嗎？ 有人有更好的選擇嗎？ 提前致謝！

Answer 1

這是你想要的嗎？

select t.*,
       sum(value) over 
           (partition by (case when exists (select 1 from tablelikethis tlt where tlt.id = 1 and tlt.rules = 'rule1') then t.rule1 end),
                         (case when exists (select 1 from tablelikethis tlt where tlt.id = 1 and tlt.rules = 'rule2') then t.rule2 end),
                         (case when exists (select 1 from tablelikethis tlt where tlt.id = 1 and tlt.rules = 'rule3') then t.rule3 end),
                         (case when exists (select 1 from tablelikethis tlt where tlt.id = 1 and tlt.rules = 'rule4') then t.rule4 end)
           )
from my_table t