簡體   English   中英

是否可以對子查詢創建的變量運行聯接?

[英]Is it possible to run a join on a variable created by a sub-query?

現在,我正在運行一個子查詢以獲取服務器的最新狀態,該子查詢通過變量last_status返回。

 //This is ran when WithLastStatusDate() is called
$query->addSubSelect('last_status', ServerStatus::select('status_id')
    ->whereRaw('server_id = servers.id')
    ->latest()
);

$servers = Server::WithLastStatusDate()
    ->OrderBy('servers.id', 'desc')
    ->where('servers.isPublic', '=', 1)
    ->get(); 

我現在想做的就是對此進行聯接,以便根據狀態表中此查詢的結果為我提供狀態的實際名稱。 我試圖做一個簡單的左聯接,但是卻收到找不到last_status列的錯誤。

$servers = Server::WithLastStatusDate()
    ->OrderBy('servers.id', 'desc')
    ->where('servers.isPublic', '=', 1)
    ->leftjoin('statuses','servers.last_status', '=', 'statuses.id')
    ->get(); 

誰能為我指出正確的方向呢?

編輯::

服務器表:

 Schema::create('servers', function (Blueprint $table) {
            $table->engine = 'InnoDB';
            $table->increments('id');
            $table->string('name');
            $table->string('url');
            $table->boolean('isPublic');
            $table->timestamps();
        });

Server_statuses表:

Schema::create('server_statuses', function (Blueprint $table) {
            $table->engine = 'InnoDB';
            $table->increments('id');
            $table->integer('server_id')->unsigned();
            $table->foreign('server_id')->references('id')->on('servers')->onDelete('cascade');
            $table->integer('status_id')->unsigned();
            $table->foreign('status_id')->references('id')->on('statuses');
            $table->timestamps();
        });

狀態表:

Schema::create('statuses', function (Blueprint $table) {
    $table->engine = 'InnoDB';
    $table->increments('id');
    $table->string('key');
    $table->string('status');
    $table->timestamps();
});

子查詢后,$ servers是什么樣的:

在此處輸入圖片說明

查詢的原始SQL:

select `servers`.*, (select `status_id` from `server_statuses` where server_id = servers.id order by `created_at` desc limit 1) as `last_status` from `servers` where `servers`.`isPublic` = '1' order by `servers`.`id` desc

編輯2 ::

    $servers = DB::table('servers as sv')
        ->join('server_statuses as ss', 'sv.id', '=', 'ss.server_id')
        ->join('statuses as st', 'ss.status_id', '=', 'st.id')
        ->WithLastStatus()
        ->OrderBy('servers.id', 'desc')
        ->where('servers.isPublic', '=', 1)
        ->get();

將LEFT JOIN與子查詢WHERE子句組合:

$servers = Server::select('servers.*', 'statuses.status as status_name')
    ->leftJoin('server_statuses', function($join) {
        $join->on('server_statuses.server_id', '=', 'servers.id')
            ->where('server_statuses.id', function($query) {
                $query->select('id')
                    ->from('server_statuses')
                    ->whereColumn('server_id', 'servers.id')
                    ->latest()
                    ->limit(1);
            });
    })
    ->leftJoin('statuses', 'statuses.id', '=', 'server_statuses.status_id')
    ->where('servers.isPublic', '=', 1)
    ->orderBy('servers.id', 'desc')
    ->get();

由於我不確定您想從查詢中得到什么,我將提供一個長解決方案並添加一些示例。 使用這些表,您應該具有以下模型:服務器模型:

class Server extends Model {
    public function statuses() {
        return $this->belongsToMany(Status::class, 'server_statuses');
    }
}

狀態模型:

class Status extends Model {
    public function servers() {
        return $this->belongsToMany(Server::class, 'server_statuses');
    }
}

示例:獲取服務器的最新狀態:

Server::find($serverId)->statuses()->latest()->first()->status;

獲取所有服務器狀態:

Server::find($serverId)->statuses;

獲取服務器的特定狀態:

Server::find($serverId)->statuses()->where('status', 'SomeStatus')->get();

獲取具有特定狀態的服務器:

Server::whereHas('statuses', function ($join) use ($status) {
    return $join->where('status', $status);
})->get();

希望你找到答案。

據我了解,您的Server模型和Status模型都與ServerStatus具有OneToMany關系。 在這種情況下,您可以在Server模型上偽造一個OneToOne關系,該關系被選擇為serverStatuses()的最新行:

class Server
{
    public function serverStatuses()
    {
        return $this->hasMany(ServerStatus::class, 'server_id', 'id');
    }

    public function latestServerStatus()
    {
        return $this->hasOne(ServerStatus::class, 'server_id', 'id')
            ->latest(); // this is the most important line of this example
                        // `->orderBy('created_at', 'desc')` would do the same
    }
}

class ServerStatus
{
    public function server()
    {
        return $this->belongsTo(Server::class, 'server_id', 'id');
    }

    public function status()
    {
        return $this->belongsTo(Status::class, 'status_id', 'id');
    }
}

class Status
{
    public function serverStatuses()
    {
        return $this->hasMany(ServerStatus::class, 'status_id', 'id');
    }
}

然后,您也可以急於加載服務器的最新狀態以及狀態本身:

Server::with('latestServerStatus.status')->get();

請注意, $server->latestServerStatus不是集合,而是一個對象,就像在普通的OneToOne關系中一樣。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM