[英]Extract IPs from multiples websites using bash and awk
我正在尋找獲取多個網站IP並將其輸出為"domain.com:","1.1.1.1"
的最佳方法,以實現此目標,我正在考慮使用nslookup
(不確定是否是最佳選擇,但我不想使用ping)
好吧,我正在嘗試類似的東西:
for domain in $(cat domains.txt)
do
nslookup $domain 8.8.8.8 | awk '/Address: ([[:digit:]]+\.){3}/{gsub(/\.$/,"",$1); printf "\"%s\",\"%s\"\n",$1,$NF}'; done
這樣,我得到以下輸出:
"Address:","64.233.190.101"
"Address:","64.233.190.138"
"Address:","64.233.190.100"
"Address:","64.233.190.139"
"Address:","64.233.190.113"
"Address:","64.233.190.102"
"Address:","98.137.246.8"
"Address:","98.138.219.231"
"Address:","72.30.35.9"
"Address:","72.30.35.10"
"Address:","98.138.219.232"
"Address:","98.137.246.7"
"Address:","93.184.216.34"
預期產量
"google.com","64.233.190.101"
"google.com","64.233.190.138"
"google.com","64.233.190.100"
"google.com","64.233.190.139"
"google.com","64.233.190.113"
"google.com","64.233.190.102"
"yahoo.com","98.137.246.8"
"yahoo.com","98.138.219.231"
"yahoo.com","72.30.35.9"
"yahoo.com","72.30.35.10"
"yahoo.com","98.138.219.232"
"yahoo.com","98.137.246.7"
"example.com","93.184.216.34"
domains.txt內容:
google.com
yahoo.com
example.com
我試圖這樣做,但是在輸出的"domain.com",
下找不到正確的域。
我不確定是否使用$ domain或awk,誰能幫助我獲得正確的語法。 請注意,我需要在"domain.com",
請求的域"domain.com",
而不是nslookup中的“ Name:
謝謝。
domain="mail.yahoo.com"
nslookup "$domain" 8.8.8.8 | awk -v n="$domain" -F ' +' '$1=="Address:"{print "\""n"\",\""$2"\""}'
輸出:
"mail.yahoo.com","87.248.116.12" "mail.yahoo.com","87.248.116.11"
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