與Ramda合並具有深度嵌套鍵的兩個數組

Question

我最近開始使用Ramda處理來自JSONAPI的響應。 對於如何使用深層嵌套的鍵合並兩個對象，我有些困惑。

例如：

拿這兩組數據，

const users = [
    {   id: 1, 
        attributes: {
            firstName: "Bob",
            lastName: "Lee"
        }, 
        relationships: {
            phone: {
                data: {
                    id: 2, 
                    type: "phone"
                }
            }
        },
        type: "users"
     },
    {   id: 2, 
        attributes: {
            firstName: "Kevin",
            lastName: "Smith"
        }, 
        relationships: {
            phone: {
                data: {
                    id: 5, 
                    type: "phone"
                }
            }
        },
        type: "users"
     },
];

const phones= [
    {   id: 2, 
        attributes: {
            phoneNumber: "123-345-6789"
        },
        type: "phones"
     },
    {   id: 5, 
        attributes: {
            phoneNumber: "987-654-4321"
        }, 
        type: "phones"
     },
];

我要創建的是一個新陣列，將相關手機添加到用戶陣列中，並帶有一個包含所有相關對象的新鍵，如下所示：

const newUser = 
[
  { id: 1,
    attributes: {
      firstName: "Bob",
      lastName: "Lee"
    },
    relationships: {
      phone: {
        data: {
          id: 2,
          type: "phones"
        }
      }
    },
    included: {
      phoneNumber: "123-345-6789"
    }
  },
  { id: 2,
    attributes: {
      firstName: "Kevin",
      lastName: "Smith"
    },
    relationships: {
      phone: {
        data: {
          id: 5,
          type: "phones"
        }
      }
    },
    type: "users",
    included: {
      phoneNumber: "987-654-4321"
    }
  }
]

我嘗試了多種方法，例如map，pick和join，但是這些對象似乎並不想按照我希望的方式進行合並。 以下代碼將兩個對象放入同一數組中，但是我似乎無法將下一步繼續前進。

const data = R.pipe(
        R.juxt([
          R.pipe(R.path(['users'])),
          R.pipe(R.path(['phones']))
        ]),
      )
}),

Answer 1

這是我的第一種方法：

 const {map, path, find, propEq, assoc} = R const addPhones = (phones, users) => map(user => { const phoneId = path(['relationships', 'phone', 'data', 'id'], user) const phone = find(propEq('id', phoneId), phones) return phone ? assoc('included', phone.attributes, user) : user }, users) const users = [{"attributes": {"firstName": "Bob", "lastName": "Lee"}, "id": 1, "relationships": {"phone": {"data": {"id": 2, "type": "phone"}}}, "type": "users"}, {"attributes": {"firstName": "Kevin", "lastName": "Smith"}, "id": 2, "relationships": {"phone": {"data": {"id": 5, "type": "phone"}}}, "type": "users"}, {"attributes": {"firstName": "Nancy", "lastName": "Johnson"}, "id": 3, "relationships": {"phone": {"data": {"id": 6, "type": "phone"}}}, "type": "users"}] const phones= [{"attributes": {"phoneNumber": "123-345-6789"}, "id": 2, "type": "phones"}, {"attributes": {"phoneNumber": "987-654-4321"}, "id": 5, "type": "phones"}, {"attributes": {"phoneNumber": "212-867-5309"}, "id": 7, "type": "phones"}] console.log(addPhones(phones, users)) 

 <script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.js"></script> 

此版本適當處理了兩個列表中的缺失值。 如果存在沒有匹配電話的用戶，則該用戶將按原樣返回，沒有included屬性。 如果有一部電話沒有匹配的用戶，則將其忽略。

這假定您可以在用戶中包括整個phone.attributes對象。 如果您只需要包含phoneNumber ，則只需稍微復雜一點，用替換明顯的行即可

    ? assocPath(['included', 'phoneNumber'], phone.attributes.phoneNumber, user)