[英]Twitter4j: Oauth wont work
努力獲取可用的twitter4j實例,但Oauth遇到問題。 我多次復制粘貼,創建了不同的應用程序和鍵/令牌,但仍然無法正常工作。 我在這里真的會做錯什么?
我的主要:
public class Main {
public static void main(String[] args) {
// write your code here
Tweeter tweet = new Tweeter();
try{
tweet.searchTweets();
} catch (TwitterException e) {
e.printStackTrace();
}
}
}
我的推特課程:
public class Tweeter {
public static Twitter GetTwitterInstance(){
String consumerKey = "**************";
String consumerSecret = "*************";
String accessToken = "***************"; // yourt token
String accessTokenSecret = "************"; // your token secre
ConfigurationBuilder cb = new ConfigurationBuilder();
cb.setDebugEnabled(true)
.setOAuthConsumerKey(consumerKey)
.setOAuthConsumerSecret(consumerSecret)
.setOAuthAccessToken(accessToken)
.setOAuthAccessTokenSecret(accessTokenSecret);
TwitterFactory tf = new TwitterFactory(cb.build());
Twitter twitter = tf.getSingleton();
return twitter;
}
public static void searchTweets() throws TwitterException{
Twitter twitter = GetTwitterInstance();
Query query = new Query("something");
QueryResult result = twitter.search(query);
List<Status> statuses = result.getTweets();
for(Status tweet: statuses){
System.out.println("User: "+tweet.getUser().getScreenName() + " Tweet: "+tweet.getText());
}
}
}
和錯誤stacktrace:
400:The request was invalid. An accompanying error message will explain why.
This is the status code will be returned during version 1.0 rate
limiting(https://dev.twitter.com/pages/rate-limiting). In API v1.1, a request
without authentication is considered invalid and you will get this response.
message - Bad Authentication data.
code - 215
Relevant discussions can be found on the Internet at:
http://www.google.co.jp/search?q=506c3b98 or
http://www.google.co.jp/search?q=11ed9ae8
TwitterException{exceptionCode=[506c3b98-11ed9ae8], statusCode=400,
message=Bad Authentication data., code=215, retryAfter=-1,
rateLimitStatus=null, version=4.0.6}
at twitter4j.HttpClientImpl.handleRequest(HttpClientImpl.java:164)
at twitter4j.HttpClientBase.request(HttpClientBase.java:57)
at twitter4j.HttpClientBase.get(HttpClientBase.java:75)
at twitter4j.TwitterImpl.get(TwitterImpl.java:1786)
at twitter4j.TwitterImpl.search(TwitterImpl.java:268)
at Tweeter.searchTweets(Tweeter.java:58)
at Main.main(Main.java:14)
打印twitter工廠的鍵/令牌將按預期提供正常的鍵/令牌,而不會出現怪異的字符或空格或其他內容。 任何幫助將不勝感激!
問題在於tf.getSingleton()
顯然未返回twitter
實例。
它應該只是Twitter twitter = tf.getInstance();
然后它起作用。
您的代碼似乎是從已知的有效代碼中剪切並粘貼的。 再次檢查是否沒有多余的字符,例如字符串末尾的空格。
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