節點Ramda +根據值查找對象

Question

可能根據值獲取對象？

在下面的示例json中，鍵名具有type ，因此基於類型的值需要獲取結果。

例如，如果type ='user'，則僅針對用戶對象而不是員工對象獲取結果。

在這里，我很努力地同時擁有密鑰（用戶和雇員），請您提出如何解決的建議。

 var list =[ {"doc":{"type":"user","Title":"test1","Relations":{"users":[{"name": "user1"},{"name": "user2"},{"name": "user3"}],"employee":[{"emp": "user2"}]}}}, {"doc":{"type":"employee","Title":"test2","Relations":{"users":[{"name": "user1"}],"employee":[{"name": "emp1"},{"name": "emp2"},{"name": "emp3"}]}}} ]; const getDetails = R.chain(R.pipe( R.path(['doc', 'Relations']), R.pick(['users', 'employee']), R.values )) const result = getDetails(list) console.log(result) 

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電流輸出：

[[{"name": "user1"}, {"name": "user2"}, {"name": "user3"}], [{"emp": "user2"}], [{"name": "user1"}], [{"name": "emp1"}, {"name": "emp2"}, {"name": "emp3"}]]

預期輸出：

[[{"name": "user1"}, {"name": "user2"}, {"name": "user3"}], [{"name": "emp1"}, {"name": "emp2"}, {"name": "emp3"}]]

Answer 1

您可以基於一組謂詞使用R.cond分支邏輯，例如您的示例中type是user還是employee 。

使用這種方法，您將需要將R.chain切換到R.map以匹配您的期望列表，除非您想要額外扁平化數組。

 const list = [ {"doc":{"type":"user","Title":"test1","Relations":{"users":[{"name": "user1"},{"name": "user2"},{"name": "user3"}],"employee":[{"emp": "user2"}]}}}, {"doc":{"type":"employee","Title":"test2","Relations":{"users":[{"name": "user1"}],"employee":[{"name": "emp1"},{"name": "emp2"},{"name": "emp3"}]}}} ] const getDetails = R.map(R.pipe( R.prop('doc'), R.cond([ [R.propEq('type', 'user'), R.path(['Relations', 'users'])], [R.propEq('type', 'employee'), R.path(['Relations', 'employee'])] ]) )) const expected = [[{"name": "user1"}, {"name": "user2"}, {"name": "user3"}], [{"name": "emp1"}, {"name": "emp2"}, {"name": "emp3"}]] console.log(R.equals(expected, getDetails(list))) 

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