[英]How can I encrypt with a RSA private key in python?
是否可以使用 pycryptodome 或任何其他庫在 python 中使用私鑰加密消息? 我知道你不應該用私鑰加密並用公鑰解密,但我的目的是用私鑰加密,以便接收者可以確定消息是由真正的作者發送的。 不僅僅是安全加密,我正在尋找某種混淆。 我想做一個消息是公開的應用程序,但只有在您擁有公鑰時才能看到它。 我試過這樣做:
from Crypto import Random
from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_OAEP
import base64
def generate_keys():
modulus_lenght = 256 * 4
private_key = RSA.generate(modulus_lenght, Random.new().read)
public_key = private_key.publickey()
return private_key, public_key
def encrypt_private_key(a_message, private_key):
encryptor = PKCS1_OAEP.new(private_key)
encrypted_msg = encryptor.encrypt(a_message)
encoded_encrypted_msg = base64.b64encode(encrypted_msg)
return encoded_encrypted_msg
def decrypt_public_key(encoded_encrypted_msg, public_key):
encryptor = PKCS1_OAEP.new(public_key)
decoded_encrypted_msg = base64.b64decode(encoded_encrypted_msg)
decoded_decrypted_msg = encryptor.decrypt(decoded_encrypted_msg)
return decoded_decrypted_msg
private_key, public_key = generate_keys()
message = "Hello world"
encoded = encrypt_private_key(message, private_key)
decoded = decrypt_public_key(encoded, public_key)
print decoded
但它引發了下一個錯誤:TypeError:這不是私鑰。
簡答
長答案
我對你的問題很好奇,然后我開始嘗試編碼
過了一會兒,我意識到如果你運行這個代碼段,你會看到它正常工作:
#!/usr/bin/env python
from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_OAEP
import base64
def generate_keys():
modulus_length = 1024
key = RSA.generate(modulus_length)
#print (key.exportKey())
pub_key = key.publickey()
#print (pub_key.exportKey())
return key, pub_key
def encrypt_private_key(a_message, private_key):
encryptor = PKCS1_OAEP.new(private_key)
encrypted_msg = encryptor.encrypt(a_message)
print(encrypted_msg)
encoded_encrypted_msg = base64.b64encode(encrypted_msg)
print(encoded_encrypted_msg)
return encoded_encrypted_msg
def decrypt_public_key(encoded_encrypted_msg, public_key):
encryptor = PKCS1_OAEP.new(public_key)
decoded_encrypted_msg = base64.b64decode(encoded_encrypted_msg)
print(decoded_encrypted_msg)
decoded_decrypted_msg = encryptor.decrypt(decoded_encrypted_msg)
print(decoded_decrypted_msg)
#return decoded_decrypted_msg
def main():
private, public = generate_keys()
print (private)
message = b'Hello world'
encoded = encrypt_private_key(message, public)
decrypt_public_key(encoded, private)
if __name__== "__main__":
main()
但是,如果您現在將最后兩行 [即鍵的作用] 更改為:
encoded = encrypt_private_key(message, private)
decrypt_public_key(encoded, public)
並重新運行程序,你會得到TypeError: No private key
讓我引用這個偉大的答案:
“事實證明,PyCrypto 只是試圖防止您在這里將一個誤認為另一個,例如 OpenSSL 或 Ruby OpenSSL 允許您同時執行以下操作:public_encrypt/public_decrypt 和 private_encrypt/private_decrypt
[...]
需要注意其他事情才能使結果在實踐中可用。 這就是為什么 PyCrypto 中有一個專用的簽名包- 這有效地完成了你所描述的,而且還處理了我提到的事情”
改編此鏈接,我來到了以下應該解決您問題的代碼:
# RSA helper class for pycrypto
# Copyright (c) Dennis Lee
# Date 21 Mar 2017
# Description:
# Python helper class to perform RSA encryption, decryption,
# signing, verifying signatures & keys generation
# Dependencies Packages:
# pycrypto
# Documentation:
# https://www.dlitz.net/software/pycrypto/api/2.6/
from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_OAEP
from Crypto.Signature import PKCS1_v1_5
from Crypto.Hash import SHA512, SHA384, SHA256, SHA, MD5
from Crypto import Random
from base64 import b64encode, b64decode
import rsa
hash = "SHA-256"
def newkeys(keysize):
random_generator = Random.new().read
key = RSA.generate(keysize, random_generator)
private, public = key, key.publickey()
return public, private
def importKey(externKey):
return RSA.importKey(externKey)
def getpublickey(priv_key):
return priv_key.publickey()
def encrypt(message, pub_key):
#RSA encryption protocol according to PKCS#1 OAEP
cipher = PKCS1_OAEP.new(pub_key)
return cipher.encrypt(message)
def decrypt(ciphertext, priv_key):
#RSA encryption protocol according to PKCS#1 OAEP
cipher = PKCS1_OAEP.new(priv_key)
return cipher.decrypt(ciphertext)
def sign(message, priv_key, hashAlg="SHA-256"):
global hash
hash = hashAlg
signer = PKCS1_v1_5.new(priv_key)
if (hash == "SHA-512"):
digest = SHA512.new()
elif (hash == "SHA-384"):
digest = SHA384.new()
elif (hash == "SHA-256"):
digest = SHA256.new()
elif (hash == "SHA-1"):
digest = SHA.new()
else:
digest = MD5.new()
digest.update(message)
return signer.sign(digest)
def verify(message, signature, pub_key):
signer = PKCS1_v1_5.new(pub_key)
if (hash == "SHA-512"):
digest = SHA512.new()
elif (hash == "SHA-384"):
digest = SHA384.new()
elif (hash == "SHA-256"):
digest = SHA256.new()
elif (hash == "SHA-1"):
digest = SHA.new()
else:
digest = MD5.new()
digest.update(message)
return signer.verify(digest, signature)
def main():
msg1 = b"Hello Tony, I am Jarvis!"
msg2 = b"Hello Toni, I am Jarvis!"
keysize = 2048
(public, private) = rsa.newkeys(keysize)
# https://docs.python.org/3/library/base64.html
# encodes the bytes-like object s
# returns bytes
encrypted = b64encode(rsa.encrypt(msg1, private))
# decodes the Base64 encoded bytes-like object or ASCII string s
# returns the decoded bytes
decrypted = rsa.decrypt(b64decode(encrypted), private)
signature = b64encode(rsa.sign(msg1, private, "SHA-512"))
verify = rsa.verify(msg1, b64decode(signature), public)
#print(private.exportKey('PEM'))
#print(public.exportKey('PEM'))
print("Encrypted: " + encrypted.decode('ascii'))
print("Decrypted: '%s'" % (decrypted))
print("Signature: " + signature.decode('ascii'))
print("Verify: %s" % verify)
rsa.verify(msg2, b64decode(signature), public)
if __name__== "__main__":
main()
最后說明:
看起來pycrypto
自 2014 年以來一直沒有積極開發,支持在 python 3.3 結束。 cryptography
現在似乎是標准。
使用cryptography
:
from cryptography.hazmat.primitives import serialization
from cryptography.hazmat.primitives.asymmetric import rsa
from cryptography.hazmat.backends import default_backend
password = b'thepassword'
key = rsa.generate_private_key(
backend=default_backend(),
public_exponent=65537,
key_size=2048
)
private_key = key.private_bytes(
serialization.Encoding.PEM,
serialization.PrivateFormat.PKCS8,
serialization.BestAvailableEncryption(password)
)
public_key = key.public_key().public_bytes(
serialization.Encoding.OpenSSH,
serialization.PublicFormat.OpenSSH
)
您所描述的稱為消息簽名,它使用私鑰/公鑰來驗證消息確實來自聲稱的發件人,並且在途中沒有被篡改。 你不必“發明”這些方法......
https://medium.com/@securegns/implementing-asymmetric-encryption-to-secure-your-project-35368049cb5f
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