無法使用PHP找出程序化MySQL預備語句錯誤

Question

我是PHP和MySQL的新手。 我的服務器具有MySQL 5.6版本。 我正在使用過程性語句（不是PDO，不是OO）。 這是我正在開發的網站上的PHP頁面，供用戶創建新帳戶。 奇怪的是，錯誤消息是在實際頁面本身（ https://mywebsite.com/create_account.php ）上返回的，而不是在服務器上的錯誤日志中返回的。

*這是我收到的錯誤消息：*

錯誤：在用戶中插入INSERT INTO用戶（用戶名，密碼，名字_名字，名字_姓氏，地址_1，地址_2，城市，州，郵政編碼，電子郵件地址，電話號碼，姓名_卡片，card_number_main，card_number_ccv，card_expire_mo，card_expire_yr）VALUES（？，？，？，？，？， ？，？，？，？，？，？，？，？，？，？，？，？ 查看與您的MySQL服務器版本相對應的手冊以獲取正確的語法以在'？，？，？，？，？，？，？，？，？，？，？，？，？，？，？，？，？附近使用） '

*這是生成錯誤消息的我的代碼：*

//
// Insert data into database
//

$sql = "INSERT INTO users (username, password, name_first, name_last, address_1, address_2, city, state, zip_code, email_address, phone_number, name_on_card, card_number_main, card_number_ccv, card_expire_mo, card_expire_yr) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
$stmt = mysqli_prepare($link, $sql);
mysqli_stmt_bind_param($stmt, "ssssssssssssssss", $param_username, $param_password, $param_name_first, $param_name_last, $param_address_1, $param_address_2, $param_city, $param_state, $param_zip_code, $param_email_address, $param_phone_number, $param_name_on_card, $param_card_number_main, $param_card_number_ccv, $param_card_expire_mo, $param_card_expire_yr);
$param_username = $username;
$param_password = $password;
$param_name_first = $name_first;
$param_name_last = $name_last;
$param_address_1 = $address_1;
$param_address_2 = $address_2;
$param_city = $city;
$param_state = $state;
$param_zip_code = $zip_code;
$param_email_address = $email_address;
$param_phone_number = $phone_number;
$param_name_on_card = $name_on_card;
$param_card_number_main = $card_number_main;
$param_card_number_ccv = $card_number_ccv;
$param_card_expire_mo = $card_expire_mo;
$param_card_expire_yr = $card_expire_yr;
mysqli_stmt_execute($stmt);

我已閱讀該手冊，但提示錯誤消息卻無濟於事。 非常感激任何的幫助。 謝謝。

Answer 1

變量聲明綁定stmt后移動？

<?php

$sql = "INSERT INTO users (username, password, name_first, name_last, address_1, address_2, city, state, zip_code, email_address, phone_number, name_on_card, card_number_main, card_number_ccv, card_expire_mo, card_expire_yr) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
$stmt = mysqli_prepare($link, $sql);

$param_username = $username;
$param_password = $password;
$param_name_first = $name_first;
$param_name_last = $name_last;
$param_address_1 = $address_1;
$param_address_2 = $address_2;
$param_city = $city;
$param_state = $state;
$param_zip_code = $zip_code;
$param_email_address = $email_address;
$param_phone_number = $phone_number;
$param_name_on_card = $name_on_card;
$param_card_number_main = $card_number_main;
$param_card_number_ccv = $card_number_ccv;
$param_card_expire_mo = $card_expire_mo;
$param_card_expire_yr = $card_expire_yr;


mysqli_stmt_bind_param($stmt, "ssssssssssssssss", $param_username, $param_password, $param_name_first, $param_name_last, $param_address_1, $param_address_2, $param_city, $param_state, $param_zip_code, $param_email_address, $param_phone_number, $param_name_on_card, $param_card_number_main, $param_card_number_ccv, $param_card_expire_mo, $param_card_expire_yr);
mysqli_stmt_execute($stmt);