[英]Zend routing issue
我正在將zend表達性網站(隨意組合)轉換為本地餐廳的zend framework 3網站。 當我在富有表現力的網站上設置路由時,我將根據如下所示的查詢參數加載位置。
website.com/location?location=xxx
在我的新網站上,路由如下所示
website.com/locations/view/xxx
我需要設置將舊網址重定向到新網址的路由。 到目前為止,我已經建立了一條尋找/ location?location = [/:location]的路由,希望它能夠識別出這條“ Segment”路由並加載適當的LocationsController。 現在,它給了我一條找不到路線的錯誤。
我的代碼如下所示。
module.config.php
namespace Application;
use Zend\Router\Http\Literal;
use Zend\Router\Http\Segment;
use Zend\ServiceManager\Factory\InvokableFactory;
return [
'router' => [
'routes' => [
'home' => [
'type' => Literal::class,
'options' => [
'route' => '/',
'defaults' => [
'controller' => Controller\IndexController::class,
'action' => 'index',
],
],
],
'locations-old' => [
'type' => Segment::class,
'options' => [
'route' => '/location?location=[/:location]',
'defaults' => [
'controller' => Controller\LocationController::class,
'action' => 'index',
],
],
],
'locations' => [
'type' => Segment::class,
'options' => [
'route' => '/locations[/:action[/:location]]',
'constraints' => [
'action' => '[a-zA-Z]*',
'location' => '[a-zA-Z]*',
],
'defaults' => [
'controller' => Controller\LocationController::class,
'action' => 'index',
],
],
],
'locations.html' => [
'type' => Literal::class,
'options' => [
'route' => '/locations.html',
'constraints' => [
'action' => '[a-zA-Z][a-zA-Z0-9_-]*',
'location' => '[a-zA-Z][a-zA-Z0-9_-]*',
],
'defaults' => [
'controller' => Controller\IndexController::class,
'action' => 'index',
],
],
],
'about' => [
'type' => Literal::class,
'options' => [
'route' => '/about',
'defaults' => [
'controller' => Controller\AboutController::class,
'action' => 'index',
],
],
],
'employ' => [
'type' => Literal::class,
'options' => [
'route' => '/employ',
'defaults' => [
'controller' => Controller\EmployController::class,
'action' => 'index',
],
],
],
'news' => [
'type' => Literal::class,
'options' => [
'route' => '/news',
'defaults' => [
'controller' => Controller\NewsController::class,
'action' => 'index',
],
],
],
],
],
'view_manager' => [
'display_not_found_reason' => true,
'display_exceptions' => true,
'doctype' => 'HTML5',
'not_found_template' => 'error/404',
'exception_template' => 'error/index',
'template_map' => [
'layout/layout' => __DIR__ . '/../view/layout/layout.phtml',
'application/index/index' => __DIR__ . '/../view/application/index/index.phtml',
'error/404' => __DIR__ . '/../view/error/404.phtml',
'error/index' => __DIR__ . '/../view/error/index.phtml',
],
'template_path_stack' => [
__DIR__ . '/../view',
],
],
];
LocationController.php
namespace Application\Controller;
use Zend\Mvc\Controller\AbstractActionController;
use Application\Model\StoreTable;
use Zend\View\Model\ViewModel;
class LocationController extends AbstractActionController
{
private $table;
public function __construct(StoreTable $table)
{
$this->table = $table;
}
public function indexAction()
{
if($_GET['location'] && $this->table->doesExist($_GET['location'])) {
$location = $_GET['location'];
$this->redirect()->toRoute('locations', ['action' => 'view', 'location' => $location])->setStatusCode(302);
} else {
$this->redirect()->toUrl('/#locations')->setStatusCode(301);
}
}
public function viewAction()
{
$location = (string) $this->params()->fromRoute('location');
$store = $this->table->getStore($location);
return new ViewModel([
'store' => $store,
]);
}
}
任何幫助將不勝感激,如果需要,我可以提供更多信息。 謝謝!
如下配置您的路線,這將是基於URL的處理,如您給定的“ website.com/location?location=xxx
”,
在下面的路徑中,“ :key
”變量表示?location=xxx
'locations-old' => [
'type' => Segment::class,
'options' => [
'route' => '/location/:key',
'defaults' => [
'controller' => Controller\LocationController::class,
'action' => 'index',
],
'constraints' => [
'key' => '[a-z0-9]+',
],
],
'child_routes' => [
'query' => ['type' => 'query'],
],
]
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