如何在NSMutableArray中對對象進行分組並在Objective-C中划分為單獨的NSMutableArray

Question

我有這樣的NSMutableArray：

// NSMutableArray *Data = (NSMUtableArray(NSDictionary))
       Data = {"Device": "A1", "Temperature": "25", "datetime": "2013.02.03"},
       {"Device": "A2", "Temperature": "25", "datetime": "2013.02.03"},         
       {"Device": "A3", "Temperature": "25", "datetime": "2013.02.03"},        
       {"Device": "A1", "Temperature": "25", "datetime": "2013.02.04"},
       {"Device": "A2", "Temperature": "25", "datetime": "2013.02.04"}.

我如何按照“日期時間”細分並將其分組到單獨的NSMutableArray中。 如上所述，情況將分為：

Data_d1 = {"Device": "A1", "Temperature": "25", "datetime": "2013.02.03"},
          {"Device": "A2", "Temperature": "25", "datetime": "2013.02.03"},
          {"Device": "A3", "Temperature": "25", "datetime": "2013.02.03"}

和

Data_d2 = {"Device": "A1", "Temperature": "25", "datetime": "2013.02.04"},
          {"Device": "A2", "Temperature": "25", "datetime": "2013.02.04"}

Answer 1

您可以使用以下代碼來實現：

 let data:[[String: String]] = [ ["Device": "A1", "Temperature": "25", "datetime": "2013.02.03"], ["Device": "A2", "Temperature": "25", "datetime": "2013.02.03"], ["Device": "A3", "Temperature": "25", "datetime": "2013.02.03"], ["Device": "A1", "Temperature": "25", "datetime": "2013.02.04"], ["Device": "A2", "Temperature": "25", "datetime": "2013.02.04"]] let dateTimeArray = data.compactMap({ $0["datetime"] }) let uniqueDateTimeArray = Array(Set(dateTimeArray)) var desiredSeparatedArray = [[[String: String]]]() for dateTime in uniqueDateTimeArray { var arrayForDateTime = [[String: String]]() for element in data { if element["datetime"] == dateTime { arrayForItem.append(element) } } desiredSeparatedArray.append(arrayForDateTime) } 

最終的desiredSeparatedArray是答案！！

Answer 2

如果您有這樣的字典數組數組：

var data = [["Device": "A1", "Temperature": "25", "datetime": "2013.02.02"],
["Device": "A2", "Temperature": "25", "datetime": "2013.02.03"],
["Device": "A3", "Temperature": "25", "datetime": "2013.02.03"],
["Device": "A1", "Temperature": "25", "datetime": "2013.02.04"],
["Device": "A2", "Temperature": "25", "datetime": "2013.02.04"]]

然后，您可以根據以下任何鍵將它們隔離：

var dateArray = data.compactMap{ $0["datetime"] }
let uDateArray = Array(Set(dateArray))
var segregatedArray = [[[String: String]]]()
for dateTime in uDateArray {
    segregatedArray.append(data.filter{$0["datetime"] == dateTime})
}
print(segregatedArray);

---

根據要求添加帶有字典數組作為原始數據的Objective-C版本。

考慮您有如下的字典數組：

 NSArray *array=@[
     @{@"Device": @"A1",@"Temperature":@"25",@"datetime":@"2013.02.03"},
     @{@"Device":@"A2",@"Temperature":@"25",@"datetime":@"2013.02.03"},
     @{@"Device":@"A3",@"Temperature":@"25",@"datetime":@"2013.02.03"},
     @{@"Device":@"A1",@"Temperature":@"25",@"datetime":@"2013.02.04"},
     @{@"Device":@"X1",@"Temperature":@"26",@"datetime":@"2013.02.07"},
     @{@"Device":@"Y1",@"Temperature":@"27",@"datetime":@"2013.02.07"},
     @{@"Device":@"A2",@"Temperature":@"25",@"datetime":@"2013.02.04"}];

然后，您可以按以下方式將它們隔離：

    NSMutableDictionary* mutableDic = [[NSMutableDictionary alloc] initWithCapacity:1];
    for (NSDictionary* dic in array) {
        NSString* dateTime = [dic valueForKey:@"datetime"];
        NSMutableArray* data = [mutableDic valueForKey:dateTime];
        if(data != nil)//data with this key avalaibe, add further.
        {
            [data addObject:dic];
        }
        else//data with this key not avalaibe, make a mutable array with this dic and add.
        {
            NSMutableArray* newData = [[NSMutableArray alloc] initWithObjects:dic, nil];
            [mutableDic setValue:newData forKey:dateTime];
        }
    }
    NSLog(@"%@", mutableDic);

您可以根據任何鍵進行隔離，只需將該鍵放在此處[dic valueForKey:@"datetime"]; 。 您可以按要求輸入Device而不是datetime 。

隔離后調試器的屏幕截圖：

Answer 3

嘗試這個

let array = Data as! [[String:String]]

let dictionary = Dictionary(grouping: array, by: {$0["datetime"]!})
var listOfArray = [[[String:String]]]()
dictionary.forEach({listOfArray.append($0.value)})

listOfArray將擁有所有數組