[英]Escape asterisk in shell script
下面的數組中的星號符號在分配給數組時會擴展到文件列表中。
u='*','john'
IFS=$',';q=($u)
for j in "${!q[@]}"
do
echo "drop user ${q[j]}"
done
輸出是:
drop user abc
drop user test.sh
drop user test1.sh
drop user john
我打算得到的是:
drop user *
drop user john
我怎么能逃過星號?
您可以使用此腳本:
u='*,john'
# read comma delimited string into an array
IFS=, read -ra q <<< "$u"
# check content of array q
declare -p q
# loop through array q
for j in "${q[@]}"
do
echo "drop user $j"
done
輸出:
declare -a q=([0]="*" [1]="john")
drop user *
drop user john
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