匹配兩個文件中的字符串，並在第一個文件中向第二個文件的行尾添加匹配字符串

Question

因此，這有點棘手，我花了一些時間試圖弄清楚。

我有兩個不同的文件，一個是rackdiag格式的，如下所示：

#file1
rackdiag {
  rack {
    42U;
    description = "1.1.1";
    1: "serverone" [4U];
    5: servertwo [2U];
    7: serverthree\nblah [3U];
  }
  rack {
    42U;
    description = "1.1.2";
    1: servertwoone [4U];
    5: "servertwotwo" [2U];
   }
 }

等等。

另一個是服務器名稱列表，如下所示：

#file2
serverone.domain.com
servertwo.domain.com
serverthree.domain.com

我正在嘗試在兩個文件之間匹配字符串，並將帶有匹配字符串的行從第一個文件插入到第二個文件的末尾，並添加了一些附加內容。 我希望它像這樣在第二個文件中結束：

serverone.domain.com #1.1.1 1: "serverone" [4U];
servertwo.domain.com #1.1.1 5: servertwo [2U];
servertwoone.domain.com #1.1.2 1: servertwoone [4U]; 

我設法做到了這一點：

#!/bin/bash

cat serverlist.txt | while read line;
do
#grep for matching strings and output entire line when match found to $line2 variable
line2=$(grep -w "$line" row01.txt)
echo "$line "#" $line2" 
done > halp.txt
exit

輸出以下內容：

servertwo.domain.com #5: servertwo.domain.com [2U];

但是我注意到由於某種原因，它缺少一些應該匹配的東西。

就像，在實際文件中我有這行

   33: servername [2U];

第二行中的這一行：

servername.blahhosting.com

當我嘗試運行腳本時，輸出僅為：

servername.blahhosting.com #

有人能幫助我讓1.1.1 / 1.1.2等出現在輸出中並弄清楚為什么它可能缺少某些匹配的行嗎？

非常感謝你！

編輯1：

rackdiag {
   rack {
       42U;
       description = "5.1.1";
       1: servertwoone [4U];
       1: "servertwoone" [4U];
       1: servertwoone\nserveronetwo [4U];
       1: "servertwoone\nserveronetwo" [4U];
       1: servertwo-1\nserverone1 [4U];
       1: "servertwo-2\nserverone2" [4U];
       1: servertwoone-1 [4U];
       1: servertwoone-2 [4U];
       1: servertwoone1 [4U];
       1: servertwoone2 [4U];
       1: servertwoone;
   }
   rack {
       42U;
       description = "5.1.2";
       1: server two one [4U];
       1: servertwoone [4U];
       1: server.two.one [4U];
   }
}

如果沒有[2U]等，並且末尾為空白，則表示為[1U]

對於帶有\\ n的名稱，這意味着服務器在物理外殼上具有多個標簽。 我認為就是這樣

Answer 1

您的問題尚不清楚，但這是正確的方法，也是解決您的問題的起點：

$ cat tst.awk
NR==FNR {
    if ( $1 == "description" ) {
        desc = $NF
        gsub(/^"|";$/,"",desc)
    }
    else if ( $1 ~ /^[0-9]+:/ ) {
        nmbr = $1
        sub(/^[[:space:]]*[^[:space:]]+[[:space:]]+/,"")

        if ( $NF ~ /\[.*\];$/ ) {
            blob = $NF
            sub(/[^[:space:]]+$/,"")
        }
        else {
            blob = "[1U];"
        }
        sub(/[[:space:]]+$/,"")

        numSrvrs = split($0,srvrs,/\\n/)
        for (srvrNr=1; srvrNr<=numSrvrs; srvrNr++) {
            srvr = srvrs[srvrNr]
            gsub(/^"|"$/,"",srvr)
            srvr2data[srvr] = "#" desc " " nmbr " " $0 " " blob
            printf "TRACE: srvr2data[%s] = <%s>\n", srvr, srvr2data[srvr]
        }
    }
    next
}
{
    srvr = $0
    sub(/\..*/,"",srvr)
    print $0, srvr2data[srvr]
}

針對前兩個樣本輸入文件運行時：

$ awk -f tst.awk file1 file2
TRACE: srvr2data[serverone] = <#1.1.1 1: "serverone" [4U];>
TRACE: srvr2data[servertwo] = <#1.1.1 5: servertwo [2U];>
TRACE: srvr2data[serverthree] = <#1.1.1 7: serverthree\nblah [3U];>
TRACE: srvr2data[blah] = <#1.1.1 7: serverthree\nblah [3U];>
TRACE: srvr2data[servertwoone] = <#1.1.2 1: servertwoone [4U];>
TRACE: srvr2data[servertwotwo] = <#1.1.2 5: "servertwotwo" [2U];>
serverone.domain.com #1.1.1 1: "serverone" [4U];
servertwo.domain.com #1.1.1 5: servertwo [2U];
serverthree.domain.com #1.1.1 7: serverthree\nblah [3U];

當使用第三個輸入文件（問題中的Edit 1 ）運行並且沒有關聯的“ file2”（因為您沒有提供文件）時，因此，您得到的只是跟蹤輸出，因為正在填充第一個文件中的數據：

$ awk -f tst.awk file3 /dev/null
TRACE: srvr2data[servertwoone] = <#5.1.1 1: servertwoone [4U];>
TRACE: srvr2data[servertwoone] = <#5.1.1 1: "servertwoone" [4U];>
TRACE: srvr2data[servertwoone] = <#5.1.1 1: servertwoone\nserveronetwo [4U];>
TRACE: srvr2data[serveronetwo] = <#5.1.1 1: servertwoone\nserveronetwo [4U];>
TRACE: srvr2data[servertwoone] = <#5.1.1 1: "servertwoone\nserveronetwo" [4U];>
TRACE: srvr2data[serveronetwo] = <#5.1.1 1: "servertwoone\nserveronetwo" [4U];>
TRACE: srvr2data[servertwo-1] = <#5.1.1 1: servertwo-1\nserverone1 [4U];>
TRACE: srvr2data[serverone1] = <#5.1.1 1: servertwo-1\nserverone1 [4U];>
TRACE: srvr2data[servertwo-2] = <#5.1.1 1: "servertwo-2\nserverone2" [4U];>
TRACE: srvr2data[serverone2] = <#5.1.1 1: "servertwo-2\nserverone2" [4U];>
TRACE: srvr2data[servertwoone-1] = <#5.1.1 1: servertwoone-1 [4U];>
TRACE: srvr2data[servertwoone-2] = <#5.1.1 1: servertwoone-2 [4U];>
TRACE: srvr2data[servertwoone1] = <#5.1.1 1: servertwoone1 [4U];>
TRACE: srvr2data[servertwoone2] = <#5.1.1 1: servertwoone2 [4U];>
TRACE: srvr2data[servertwoone;] = <#5.1.1 1: servertwoone; [1U];>
TRACE: srvr2data[server two one] = <#5.1.2 1: server two one [4U];>
TRACE: srvr2data[servertwoone] = <#5.1.2 1: servertwoone [4U];>
TRACE: srvr2data[server.two.one] = <#5.1.2 1: server.two.one [4U];>

您沒有告訴我們“ [4U]”字段是什么，所以我將其命名為blob顯然將其更改為任何內容。