如何將值傳遞到JPQL查詢中？

Question

我正在測試，它將檢查對象是否已保存到數據庫中。 測試將用唯一值保存對象，然后我要從數據庫中獲取該對象並檢查其是否不為null。 ID是自動生成的，因此我需要按名稱查找此對象。

我的測試看起來像這樣：

@Test
public void shouldAddNewEmployee(){

    String firstNameTest = "Jon";
    String lastNameTest = "Doe";
    double salary1test = 10.0;
    String salary2test = "10.00";
    String localityTest = "LosAngeles";
    String zipCodeTest = "00-000";
    String streetTest = "LosAngeles str.";
    int streetNumberTest = 10;

    Employee testEmployee = new Employee(
            firstNameTest,
            lastNameTest,
            salary1test,
            salary2test,
            localityTest,
            zipCodeTest,
            streetTest,
            streetNumberTest);

    EmployeeRepository.addNewEmployeeFromCLI(testEmployee);

    String customQueryFindJonDoe = "select e from Employee e where e.firstName = Jon and e.lastName = Doe";
    EntityManager entityManager = JPAUtils.openEntityManager();

    List<Employee> foundJonDoe = entityManager.createQuery(customQueryFindJonDoe).getResultList();

    Assertions.assertNotEquals(null, foundJonDoe);

    if (entityManager.isOpen()) {
        entityManager.close();
    }


} 

運行后我得到錯誤：

引起原因：com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException：'where子句'中的未知列'Jon'

該查詢應如何顯示？

Answer 1

您必須在查詢上設置參數：

String customQueryFindJonDoe = 
       "select e from Employee e where e.firstName = :firstname and e.lastName = :lastName";
EntityManager entityManager = JPAUtils.openEntityManager();

TypedQuery<Employee> q = entityManager.createQuery(customQueryFindJonDoe, Employee.class);
q.setParameter("firstname", "Jon");
q.setParameter("lastName", "Doe");

List<Employee> foundJonDoe = q.getResultList();

有關查詢的更多信息，您可以在這里找到：

https://docs.oracle.com/javaee/7/tutorial/persistence-querylanguage002.htm#BNBRG https://www.objectdb.com/java/jpa/query

或者您購買一本書https://www.apress.com/de/book/9781484234198