轉換清單 <Object> 列出 <HashMap<String,Double> &gt;用於json數組

Question

我有一個Json，如下所示：-

 {
      "componentModelData": {
        "modelNumber": "ABC",
        "modelName": "",
        "modelDescription": "",
        "modelVendor": null,
        "componentName": "HELO"
      },
      "revisionData": {
        "revisionName": "rev12",
        "revisionComment": "Comment",
        "modifiedBy": "2323553"
      }, 
      "configData": [{"nodes":2085,"FxPOS-SX":16.5051,"FxPOS-SY":11.0479,"FxPOS-SZ":115.3421,"FxPOS-SXY":-13.8094,"FxPOS-SYZ":36.0105
      },{"nodes":2085,"FxPOS-SX":16.5051,"FxPOS-SY":11.0479,"FxPOS-SZ":115.3421,"FxPOS-SXY":-13.8094,"FxPOS-SYZ":36.0105}]
    }

DataMapping.java

@Getter
@Setter
@JsonSerialize
@NoArgsConstructor
@AllArgsConstructor
public class DataMapping implements Serializable {
    /**
     * 
     */
    private static final long serialVersionUID = -2635323042843403966L;
    @JsonProperty("componentModelData")
    @Valid
    public ComponentModelDTO componentModelDTO;
    @JsonProperty("revisionData")
    @Valid
    public RevisionDTO revisionDTO;
    @JsonProperty("configData")
    private List<Object> configData;
}

我想將configData列表轉換為List<HashMap<String,Double>> list ，其中String是像'nodes，FxPOS-SX，FxPOS-SY'這樣的鍵，而value是它們各自的值。

誰能幫我實現這個目標嗎？

Answer 1

只需將List<Object>替換為List<Map<String,Double>> 。 傑克遜將為您完成艱苦的工作：

@JsonProperty("configData")
private List<Map<String, Double>> configData;