PHP數組計算值的唯一出現次數

Question

我有以下數組：

$booking_array = array(

    "2018-09-01"=>array("360","360","360"),
    "2018-09-02"=>array("360","360"),
    "2018-09-03"=>array("360","520"),
    "2018-09-04"=>array("360","360"),
    "2018-09-05"=>array("360","520","520"),

);

echo '<pre>',print_r($booking_array),'</pre>';

我只想獲得整個數組中特定值出現次數最多的情況。

因此，例如“ 360”的最高出現次數是“ 3”，而“ 520”的最高出現次數是“ 2”。

我正在使用array_count_values像這樣：

foreach($booking_array as $key => $val) {

    print_r(array_count_values($val));

}

哪個輸出：

Array
(
    [360] => 3
)

Array
(
    [360] => 2
)

Array
(
    [360] => 1
    [520] => 1
)

Array
(
    [360] => 2
)

Array
(
    [360] => 1
    [520] => 2
)

但是我不明白如何只取最高值並將其轉換為 ：

Array
(
    [0] => 360
    [1] => 360
    [2] => 360
    [3] => 520
    [4] => 520
)

Answer 1

我認為這是找到所需值的最簡單方法。

這使用array_count_values並對降序排列的數組進行排序，並獲取第一個項目鍵。

foreach($booking_array as $booking) {
    $array_count=array_count_values($booking);
    arsort($array_count); // sort it descending
    $result[] = key($array_count);  // get first items key
}

var_dump($result);

https://3v4l.org/WrkRf

Answer 2

首先，我們創建一個小函數來簡化事情：

 function mergeIfGreaterThan($x,$y){
    /*
        this function merge two arrays .Each existing value of $x is 
        replaced by its corresponding in $y if it is greater than it.If a value doesn't
        exist in $x  but exists in $y it is automatically added to $x
    */
    if(!is_array($x)||!is_array($y)) return false;
    foreach($x as $k=>$v){
        if(isset($y[$k])){
            if($y[$k]>$v)
                $x[$k]=$y[$k];
            unset($y[$k]);
        }

    }
    if(!empty($y))
    foreach($y as $k=>$v){
        $x[$k]=$v;
    }
    return $x;
}

給定此數組：

$booking_array = array(

    "2018-09-01"=>array("360","360","360"),
    "2018-09-02"=>array("360","360"),
    "2018-09-03"=>array("360","520"),
    "2018-09-04"=>array("360","360"),
    "2018-09-05"=>array("360","520","520"),

);

我們這樣處理：

$x=array();//create an empty array
foreach($booking_array as $value){//grab the max number of occurences of each value 
    $x=mergeifgreaterthan($x,array_count_values($value)); 
}
$result=array();//create another empty array to contain the result
foreach($x as $k=>$v){//loop through the array of number of occurences
    for($i=$v;$i>0;$i--){//append the value to the result array the number of times each value occurs
        $result[]=$k;
    }
}
print_r($result);

輸出：

Array
(
    [0] => 360
    [1] => 360
    [2] => 360
    [3] => 520
    [4] => 520
)

Answer 3

遵循此步驟

步驟1：創建一個多維數組來存儲值並且存在的次數最多

第2步：使用Forloop或Foreach遍歷數組

步驟3：從數組中找到最大值並更新多維數組

步驟4：根據需要使用多維數組進行打印

如果您有5個存在320和3個存在540，那么

    $a=array();
    for($i=0;$i>arraycount;$i++)
       {
          array_push($a,"value");
       }

    print_r($a);

Answer 4

$booking_array = array(

    "2018-09-01"=>array("520","360","360","360"),
    "2018-09-02"=>array("360","360"),
    "2018-09-03"=>array("360","520"),
    "2018-09-04"=>array("360","360"),
    "2018-09-05"=>array("360","520","520"),

);

echo '<pre>',print_r($booking_array),'</pre>';

foreach($booking_array as $booking) {
    $array_count=array_count_values($booking);
    $value = max($array_count);
    $key = array_search($value, $array_count);
    echo $key.'--'.$value.'times'.'<br/>';

}    

嘗試這個