[英]How can I use `phone number` and `otp` in "django-rest-framework-simplejwt" instead of `username` and `password` to generate token?
[英]return token after registration with django-rest-framework-simplejwt
我正在使用django-rest-framework-simplejwt,想知道注冊用戶后是否可以返回令牌?
這篇文章有另一個jwt包的解決方案,我想知道如何為simplejwt做類似的事情?
謝謝
我剛剛解決了自己的問題。 讓我知道您是否有任何意見。 謝謝!
class RegisterUserSerializer(serializers.ModelSerializer):
"""Serializer for creating user objects."""
tokens = serializers.SerializerMethodField()
class Meta:
model = models.User
fields = ('id', 'password', 'email', 'tokens')
extra_kwargs = {'password': {'write_only': True}}
def get_tokens(self, user):
tokens = RefreshToken.for_user(user)
refresh = text_type(tokens)
access = text_type(tokens.access_token)
data = {
"refresh": refresh,
"access": access
}
return data
def create(self, validated_data):
user = models.User(
email=validated_data['email']
)
user.set_password(validated_data['password'])
user.save()
return user
views.py
class UserListView(generics.ListCreateAPIView):
"""Handles creating and listing Users."""
queryset = User.objects.all()
def create(self, request, *args, **kwargs):
serializer = RegisterUserSerializer(data=request.data)
if serializer.is_valid():
self.perform_create(serializer)
return Response(serializer.data, status=status.HTTP_201_CREATED)
return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
我猜,您可以執行以下操作:
def custom_registration_view(request):
//code to validate & register your user
payload = jwt_payload_handler(user)
return HttpResponse(jwt_encode_handler(payload), 201)
您可以在設置文件中指定的payload_handler,encode_handler和decode_handler。
另一個可能的解決方案是:
在你看來
from rest_framework_simplejwt.serializers import TokenObtainPairSerializer
from rest_framework_simplejwt.tokens import AccessToken, RefreshToken
@login_required
def index(request):
tokenr = TokenObtainPairSerializer().get_token(request.user)
tokena = AccessToken().for_user(request.user)
return render(request,'myview/index.html', {"refresh" : str(tokenr),"access" : str(tokena)} )
我使用@login_required只是為了確保我們有一個request.user身份驗證,但是您可以通過dict來代替
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.