檢查並添加數組對象中的屬性

Question

我在下面有一個非常具體的格式細節的對象/輸出：

result = 
AB: [ 0:{Name: "Tom", team:"Spirit", position: "Defender", score: 22 }
    1:{Name: "Paul", team:"Vikings", position: "center" }
    2:{Name: "Jim", team:"United", position: "Wing", }
    3:{Name: "Greg", team:"Crusaders", position: "Fullback", score: 54}
    4:{Name: "Tim", team:"Vikings", position: "Fullback", score: 77 }
    ]
CD: [0:{...},1:{...},2:{...},3:{...},4:{...}]
EF: [0:{...},1:{...},2:{...},3:{...},4:{...}]
GH: [0:{...},1:{...},2:{...},3:{...},4:{...}]

結果有嵌套數組。 在某些輸出上， score的屬性不存在，但我需要它 - 如果它不存在，我需要將它默認添加為score:""如果它在那里，那么就不要管它。

我已經能夠添加score的屬性，但只能在結果對象的頂層，例如

...
    GH: [0:{...},1:{...},2:{...},3:{...},4:{...}]
    score:""

經過

 if(result.hasOwnProperty("score")) {
     alert('Item has already that property');
 } else {
     result.score = "" ;
 }

我可以通過（下面）定位特定路徑，但我想將其應用於所有路徑：

 if(finalResult['AB'][1].hasOwnProperty("durabilityScore")) {
    alert('Item has already that property');
} else {
    finalResult['AB'][1].durabilityScore = 'value';
}

如果有幫助，我正在使用 Lodash。 謝謝

Answer 1

您可以迭代對象和數組的值。 然后檢查該屬性是否存在，如果不存在則賦值。

此解決方案不會覆蓋虛假值（ 0 、 '' 、 false 、 undefined 、 null ），如果使用默認檢查，則會發生這種情況，例如

o.score = o.score || ''

 var result = { AB: [{ Name: "Tom", team:"Spirit", position: "Defender", score: 22 }, { Name: "Paul", team:"Vikings", position: "center" }, { Name: "Jim", team:"United", position: "Wing" }, { Name: "Greg", team:"Crusaders", position: "Fullback", score: 54 }, { Name: "Tim", team:"Vikings", position: "Fullback", score: 77 }] }; Object.values(result).forEach(a => a.forEach(o => 'score' in o || (o.score = ''))); console.log(result);

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