[英]How to iterate two array at same time using ngFor in angular?
我必須將對象數組作為來自node.js的有效負載,並將其存儲在不同的變量中並進行迭代,但是* ngFor僅迭代第一個循環而不是第二個循環,因此如何在相同的div status下進行初始化。component.html
<div *ngFor="let payload1 of payload1;let payload2 of payload2;">
<h4>{{payload2.username}}</h4>
<h4>{{payload1.date}}</h4>
</div>
status.component.ts
payload1 = [];
payload2 = [];
ngOnInit() {
this.statusService.getStatusDetails(this.statusObj).subscribe(
(data) => {
if(data.status == 26){
this.payload1 = data.payload[0];
this.payload2 = data.payload[1];
}
}
);
}
我認為,如果您的有效載荷長度相同且順序匹配(您的問題似乎暗示確實如此),則此方法應該有效
<div *ngFor="let p of payload1;let i = index">
<h4>{{payload2[i].username}}</h4>
<h4>{{payload1[i].date}}</h4>
</div>
為什么不從中制作單個陣列呢?
payload = [];
ngOnInit() {
this.statusService.getStatusDetails(this.statusObj).subscribe(
(data) => {
if(data.status == 26){
this.payload = data.payload[0]
.map((item, index) => ({ ...item, ...data.payload[1][index] }));
}
}
);
}
片段證明它有效:
const d1 = [ { id: 0 }, { id: 1 }, ]; const d2 = [ { name: '0' }, { name: '1' }, ]; const d3 = d1.map((item, index) => ({ ...item, ...d2[index] })); console.log(d3);
如果陣列的長度不同,您甚至可以構建此合並的有效負載。
const d1 = [ { id: 0 }, { id: 1 }, ]; const d2 = [ { name: '0' }, { name: '1' }, { name: '2' }, ]; const longest = d1.length > d2.length ? d1 : d2; const shortest = d1.length <= d2.length ? d1 : d2; const d3 = longest.map((item, index) => ({ ...item, ...shortest[index] })); console.log(d3);
角版本:
payload = [];
ngOnInit() {
this.statusService.getStatusDetails(this.statusObj).subscribe(
(data) => {
if(data.status == 26){
const longest = data.payload[0].length > data.payload[1].length ?
data.payload[0] : data.payload[1];
const shortest = data.payload[0].length <= data.payload[1].length ?
data.payload[0] : data.payload[1];
this.payload = longest
.map((item, index) => ({ ...item, ...shortest[index] }));
}
}
);
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.