使用getLinkUrl（offset）的Google Apps腳本問題

Question

我試圖弄清楚如何在Google Apps腳本中使用getLinkUrl(offset) 。

我在這里找到了參考-http: //googlescriptreference.com/Document/Text/getlinkurloffset/ ，但是我找不到在線示例。

該GAS在日志中返回Paragraph

var paragraph = tableCell.getChild(0);

該GAS返回日志中the text string in the paragraph中的the text string in the paragraph

var paragraphText = paragraph.getText();

該GAS在日志中返回NULL

var paragraphText = paragraph.getLinkUrl();

此GAS返回錯誤（找不到方法getLinkUrl（number）。），日志中沒有任何內容

var paragraphText = paragraph.getLinkUrl(2);

有人可以幫我了解如何使用getLinkUrl(offset)嗎？

謝謝你的幫助！

Answer 1

我試圖直接在段落元素上使用getLinkUrl(offset) （不起作用的示例），但是我需要在getLinkUrl(offset)之前使用asText()方法。

無法運作

var paragraphText = paragraph.getLinkUrl(2);

工作

var paragraphText = paragraph.asText().getLinkUrl(2);

Google文件 https://docs.google.com/document/d/136G549zIYPYBndXs70ZnR_wEFg5fPST9ZGsOlTgmDyM/edit

//Works if link is on a word or words instead of entire paragraph

function myFunctionP1() {
  //Find out how many Children there are
  var body = DocumentApp.getActiveDocument().getBody();
  Logger.log(body.getNumChildren());

  //Find out which child is table
  var table = body.getChild(2); //table is child#2
  Logger.log(table);

  //Find tableCell inside of table
  var tableCell = table.getChild(0).getChild(0); //tableCell
  Logger.log(tableCell)

  //Find paragraph inside of tableCell 
  //I think, but I'm not sure, the HYPERLINK will be found somewhere within the PARAGRAPH element. But I can't figure out how to get to it.
  var paragraph = tableCell.getChild(0); //paragraph element
  Logger.log(paragraph)

  //Get paragraph text 
  var paragraphText = paragraph.asText().getLinkUrl(2); //paragraph text
  Logger.log(paragraphText)


}



//Works if link is on entire paragraph
//Works if link is on entire paragraph
//Works if link is on entire paragraph
function myFunctionP2() {
  //Find out how many Children there are
  var body = DocumentApp.getActiveDocument().getBody();
  Logger.log(body.getNumChildren());

  //Find out which child is table
  var table = body.getChild(4); //table is child#2
  Logger.log(table);

  //Find tableCell inside of table
  var tableCell = table.getChild(0).getChild(0); //tableCell
  Logger.log(tableCell)

  //Find paragraph inside of tableCell 
  //I think, but I'm not sure, the HYPERLINK will be found somewhere within the PARAGRAPH element. But I can't figure out how to get to it.
  var paragraph = tableCell.getChild(0); //paragraph element
  Logger.log(paragraph)

  //Get paragraph text 
  var paragraphText = paragraph.getText(); //paragraph text
  Logger.log(paragraphText)

  //Get HYPERLIINK from paragraph text 
  var paragraphHYPERLINK = paragraph.getLinkUrl(); //paragraph text
  Logger.log(paragraphHYPERLINK)  

}

@Tanaike幫助我找到了這個解決方案。 https://stackoverflow.com/users/7108653/tanaike