我正在嘗試用python創建一個簡單的程序，但是我卡住了

Question

我正在嘗試使用python創建一個非常簡單的程序，但是它在錯誤窗口中指出語法無效。 我不明白這是怎么回事：

print('What is your name?')
YourName = input()
if YourName == "Alice":
    print('Hello Alice')
elif print('How old are you?')
    age = input()
elif age < 4:
        print('And you know how to write at young age!')

Answer 1

嘗試這個：

print('What is your name?')
YourName = input()
if YourName == "Alice":
    print('Hello Alice')
else:
    print('How old are you?')
    age = int(input())
    if age < 4:
        print('And you know how to write at young age!')

一線：

print("Hello Alice") if input("What is your name ")=="Alice" else print('And you know how to write at young age!') if int(input("How old are you? "))<4 else None

Answer 2

您的代碼有問題

歡迎！ 以下行是錯誤的：

elif print('How old are you?')

這背后有兩個主要原因：

1. print('How old are you?')不是正常情況。 盡管從技術上講這很好，因為編譯器會將其評估為None類型，並將其視為False ，但您可能想用概念上有意義的東西替換該部分。

2. 你錯過了后一個冒號elif 。 例如：

    elif (int(input()) < 4): #your code 

解

print('What is your name?')
YourName = input()
if YourName == "Alice":
    print('Hello Alice')
else:
    print('You are not Alice! How old are you?')
    if int(input()) < 4:
        print('You know how to write at young age!')