[英]How to launch JUnit 5 (Platform) from the command line (without Maven/Gradle)?
我想從命令行運行一個包含JUnit 5測試的類。 不幸的是,我有一些外部依賴項阻止我使用Maven,Gradle或其他構建系統。
在JUnit 4中,我可以完成這個
java .:"lib/*" org.junit.runner.JUnitCore TestClass
JUnit 5有相同的功能嗎? 我只想知道測試是否成功與IntelliJ中的運行時間相似。
TestClass.java
import org.junit.jupiter.api.AfterEach;
import org.junit.jupiter.api.BeforeAll;
import org.junit.jupiter.api.BeforeEach;
import org.junit.jupiter.api.Test;
import java.util.ArrayList;
import java.util.Collections;
import static org.junit.jupiter.api.Assertions.*;
public class TestClass {
private static ArrayList<Student> students;
private static ArrayList<Student> inAgeOrderStudents;
private static ArrayList<Student> inNameOrderStudents;
@BeforeAll
static void setUp(){
initializeStudents();
initSortedAgeStudents();
initSortedNameStudents();
}
@BeforeEach
void reloadStudents() {
Collections.shuffle(students);
}
static void initializeStudents(){
students = new ArrayList<Student>();
students.add(new Student(18, "Tim"));
students.add(new Student(18, "Tim"));
students.add(new Student(16, "Jean"));
students.add(new Student(14, "Lin"));
students.add(new Student(19, "Sam"));
}
static void initSortedAgeStudents(){
inAgeOrderStudents = new ArrayList<Student>();
inAgeOrderStudents.add(new Student(14, "Lin"));
inAgeOrderStudents.add(new Student(16, "Jean"));
inAgeOrderStudents.add(new Student(18, "Tim"));
inAgeOrderStudents.add(new Student(18, "Tim"));
inAgeOrderStudents.add(new Student(19, "Sam"));
}
static void initSortedNameStudents(){
inNameOrderStudents = new ArrayList<Student>();
inNameOrderStudents.add(new Student(16, "Jean"));
inNameOrderStudents.add(new Student(14, "Lin"));
inNameOrderStudents.add(new Student(19, "Sam"));
inNameOrderStudents.add(new Student(18, "Tim"));
inNameOrderStudents.add(new Student(18, "Tim"));
}
@Test
void testMergeSort() {
assertNotEquals(students, inAgeOrderStudents);
StudentSortSearch.mergesort(students,StudentSortSearch.SortSearchCriteria.AGE);
assertEquals(14,students.get(0).getAge());
assertEquals(19,students.get(4).getAge());
assertEquals(students, inAgeOrderStudents);
assertEquals(true,students.equals(inAgeOrderStudents));
}
@Test
void testQuickSort() {
StudentSortSearch.quickSort(students,StudentSortSearch.SortSearchCriteria.NAME);
assertEquals("Jean",students.get(0).getName());
assertEquals("Tim",students.get(4).getName());
assertEquals(students, inNameOrderStudents);
}
@Test
void testBinarySearch() {
StudentSortSearch searcher = new StudentSortSearch();
ArrayList<Student> searchResults = searcher.binarySearch(students, 18);
assertEquals(2, searchResults.size());
assertEquals(18,searchResults.get(1).getAge());
assertEquals(18,searchResults.get(0).getAge());
searchResults = searcher.binarySearch(students, "Lin");
assertEquals(1, searchResults.size());
assertEquals(14,searchResults.get(0).getAge());
}
}
當然,使用ConsoleLauncher
。
ConsoleLauncher
是一個命令行Java應用程序,允許您從控制台啟動JUnit平台 。 例如,它可用於運行JUnit Vintage和JUnit Jupiter測試並將測試執行結果打印到控制台。包含所有依賴項的可執行文件
*junit-platform-console-standalone-<version>.jar*
發布在junit-platform-console-standalone目錄下的中央Maven存儲庫中。 您可以運行獨立的ConsoleLauncher,如下所示。
java -jar junit-platform-console-standalone-<version>.jar <Options>
有關選項的詳細信息,請參閱https://junit.org/junit5/docs/current/user-guide/#running-tests-console-launcher 。
根據您的示例量身定制並使用JUnit Platform 1.3.1
版,命令可能如下所示:
$ mkdir out
$ javac -d out Student.java StudentSortSearch.java
$ javac -d out -cp out:junit-platform-console-standalone-1.3.1.jar TestClass.java
$ java -jar junit-platform-console-standalone-1.3.1.jar --class-path out --scan-class-path
╷
├─ JUnit Jupiter ✔
│ └─ TestClass ✔
│ └─ test() ✔
└─ JUnit Vintage ✔
Test run finished after 67 ms
...
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