mysql-如何在字段中選擇具有0或1值的記錄集，僅在值存在的情況下才選擇值1的記錄？

Question

我有一個表“ wordstyped”，其中包含“ idBook”，“ guidUser”，“ bookmarkLetter”，“ letter”，“ attemptWrong”和“ isCorrect”。

idBook  guidUser  bookmarkLetter  letter  attemptWrong   isCorrect
-------------------------------------------------------------------
1       1         100             a       2              0
1       1         100             a       3              0
1       1         100             a       3              1
1       1         101             b       6              0
1       1         101             b       2              0
2       2         101             b       3              0
2       3         152             d       7              0
3       3         153             e       2              0

我想選擇所有記錄，它們的所有字段都包含最大數量的“ attemptWrong”，但三元組分別為“ idBook”，“ guidUser”和“ bookmarkLetter”。 我已經用這個查詢完成了

SELECT DISTINCT w1.bookmarkletter, w1.attemptsWrong
FROM wordstyped w1 INNER JOIN ( SELECT bookmarkLetter, guidUser, idBook, 
MAX(attemptsWrong) AS maxAttemptsWrong 
FROM wordstyped 
GROUP BY bookmarkLetter, guidUser, idBook ) w2 
ON w1.bookmarkLetter = w2.bookmarkLetter AND w1.guidUser = w2.guidUser 
AND w1.guidUser = '1' 
AND w1.idBook ='1'
AND w1.attemptsWrong = w2.maxAttemptsWrong AND w1.bookmarkLetter >=0
AND w1.bookmarkLetter <=200 ORDER BY `w1`.`bookmarkletter` ASC

就像這個小提琴一樣http://sqlfiddle.com/#!9/238794/2

現在，我也要選擇“ isCorrect”，如果至少一個記錄的ha值為isCorrect = 1，則選擇值為1；如果所有記錄的值為0，則選擇0。

如果我在示例情況下將w1.isCorrect添加到第一個select語句中

SELECT DISTINCT w1.bookmarkletter, w1.attemptsWrong, w1.isCorrect
FROM wordstyped w1 INNER JOIN ( SELECT bookmarkLetter, guidUser, idBook, 
MAX(attemptsWrong) AS maxAttemptsWrong 
FROM wordstyped 
GROUP BY bookmarkLetter, guidUser, idBook ) w2 
ON w1.bookmarkLetter = w2.bookmarkLetter AND w1.guidUser = w2.guidUser 
AND w1.guidUser = '1' 
AND w1.idBook ='1'
AND w1.attemptsWrong = w2.maxAttemptsWrong AND w1.bookmarkLetter >=0
AND w1.bookmarkLetter <=200 ORDER BY `w1`.`bookmarkletter` ASC

（ http://sqlfiddle.com/#!9/238794/1 ），這組記錄

idBook  guidUser  bookmarkLetter  letter  attemptWrong   isCorrect
-------------------------------------------------------------------
1       1         101             b       6              0
1       1         101             b       2              0
2       2         101             b       3              0

正確返回

bookmarkLetter    attemptWrong    isCorrect
-------------------------------------------------------------------
101               6               0

而這組記錄

idBook  guidUser  bookmarkLetter  letter  attemptWrong   isCorrect
-------------------------------------------------------------------
1       1         100             a       2              0
1       1         100             a       3              0
1       1         100             a       3              1

回報

bookmarkLetter    attemptWrong    isCorrect
-------------------------------------------------------------------
100               3               0
100               3               1

代替

bookmarkLetter    attemptWrong    isCorrect
-------------------------------------------------------------------
100               3               1

如何獲得第二個結果？

編輯：我有isCorrect 1的情況總是像示例中一樣發生，即我有兩條帶有tryWrong的記錄，這是最大值，一個記錄是isCorrect = 0，一個記錄是isCorrect = 1

Answer 1

嘗試使用匯總和分組依據

http://sqlfiddle.com/#!9/238794/4

SELECT w1.bookmarkletter, max(w1.attemptsWrong), max(w1.isCorrect) 
  FROM wordstyped w1 INNER JOIN 
  ( SELECT bookmarkLetter, guidUser, idBook, MAX(attemptsWrong) AS maxAttemptsWrong 
    FROM wordstyped 
    GROUP BY bookmarkLetter, guidUser, idBook ) w2 
ON w1.bookmarkLetter = w2.bookmarkLetter AND w1.guidUser = w2.guidUser 
AND w1.guidUser = '1' 
AND w1.idBook ='1'
AND w1.attemptsWrong = w2.maxAttemptsWrong AND w1.bookmarkLetter >=0
AND w1.bookmarkLetter <=200 
group by w1.bookmarkletter
ORDER BY `w1`.`bookmarkletter` ASC