PHP：將兩個multimensioanl數組合並為一個

Question

我嘗試創建一個多維數組（ $list ），它應該如下所示：

[
  {"uri": "http://www.example.com/1", "traverseCount": "1"},
  {"uri": "http://www.example.com/2", "traverseCount": "1"},
  {"uri": "http://www.example.com/3", "traverseCount": "1"}
]

但是，我不知道如何從以下數據中實現這一目標。 這兩個數據源來自兩個If-Else並嘗試為每個案例創建一個多維數組。 但是，最后，我想生成一個多維數組，它將兩個多維數組與連續有序鍵組合在一起。 （所以，從上面的例子中， http://www.example.com/1和http://www.example.com/2來自1的結果Else-If和HTTP：//www.example .com / 3來自第二個Else-If ）。 棘手的是，在Else-If中有foreach 。

// Create an empty multidimentional array to accommodate 2 datasets (2 If-Else cases) below:
$traverseCount = 1;
$list = array(
  array(),
  array()
);
//This is the first data source. Say, it returns 2 URIs when doing the foreach loop:
$match = $graph->resourcesMatching('skos:exactMatch');
if (isset($match) == true && count($match) > 0){
  $graphuris = $match[0]->all('skos:exactMatch');
  echo '<b>skos:exactMatch Links: </b><br>';
  foreach ($graphuris as $uris) {
    $counter = 0;
    $list[$counter][0] = $uris->__toString();
    $list[$counter][1] = $traverseCount;
    $counter++;
    echo '<a href="'.$uris.'" target="_blank">'.$uris.'</a><br>';
  }
}
else {
  echo '<p>No skos:exactMatch found</p>';
}
//This is the second data source, whose multidimensional array should be added to the end of the previous multidimensional array 
$match2 = $graph->resourcesMatching('rdfs:seeAlso');
if (isset($match2) == true && count($match2) > 0){
  $graphuris2 = $match2[0]->all('rdfs:seeAlso');
  echo '<b>rdfs:seeAlso Links: </b><br>';
  foreach ($graphuris2 as $uris2) {
    $counter = 0;
    $list[$counter][0] = $uris2->__toString();
    $list[$counter][1] = $traverseCount;
    $counter++;
    echo '<a href="'.$uris2.'" target="_blank">'.$uris2.'</a><br>';
  }
}
else{
  echo '<p>No rdfs:seeAlso found</p><br>';
}
// $traverseCount is always 1 until here, but it needs to add 1 for the next script to run.
$traverseCount++;

Answer 1

它不需要那么復雜。 添加到數組可以完成，而不需要像這樣的$counter 。

// Create an empty multidimentional array to accommodate 2 datasets (2 If-Else cases) below:
$traverseCount = 1;

$list = array();
//This is the first data source. Say, it returns 2 URIs when doing the foreach loop:
$match = $graph->resourcesMatching('skos:exactMatch');
if (isset($match) == true && count($match) > 0){
  $graphuris = $match[0]->all('skos:exactMatch');
  echo '<b>skos:exactMatch Links: </b><br>';
  foreach ($graphuris as $uris) {

    $list[] = array('uri'           => $uris->__toString(), 
                    'traversecount' => $traverseCount
                    );

    echo '<a href="'.$uris.'" target="_blank">'.$uris.'</a><br>';
  }
}
else {
  echo '<p>No skos:exactMatch found</p>';
}
//This is the second data source, whose multidimensional array should be added to the end of the previous multidimensional array 
$match2 = $graph->resourcesMatching('rdfs:seeAlso');
if (isset($match2) == true && count($match2) > 0){
  $graphuris2 = $match2[0]->all('rdfs:seeAlso');
  echo '<b>rdfs:seeAlso Links: </b><br>';
  foreach ($graphuris2 as $uris2) {
    $list[] = array('uri'           => $uris2->__toString(), 
                    'traversecount' => $traverseCount
                    );

    echo '<a href="'.$uris2.'" target="_blank">'.$uris2.'</a><br>';
  }
}
else{
  echo '<p>No rdfs:seeAlso found</p><br>';
}
// $traverseCount is always 1 until here, but it needs to add 1 for the next script to run.
$traverseCount++;

我對$traverseCount感到有點困惑，因為在完成兩個循環之前，代碼似乎沒有改變。

Answer 2

您總是在每次迭代中將此$counter重置為0。 而只是將新元素追加到數組：

$list = [];

if () {
    foreach () {
        $list[] = [
            $uris->__toString(),
            $traverseCount
        ];
    }
}

這里我不使用counter，只需使用$list[]向數組添加新元素，索引將自動遞增。

$uris->__toString()和$traverseCount自動放到0和1索引

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我沒有看到你的$traverseCount如何改變，因為它在開始時分配為1，並且只在最后它遞增。