返回一列中值相等而另一列中值不同的行

Question

我正在嘗試返回符合此條件的結果

• 具有2個不同ColorCode相同ProfileType

我當前的查詢返回所有ProfileTypes和ColorCodes

ProfileType | ColorCode

SPT1        | 8XYZ
SPT1        | 1XYZ
SPT2        | 4XYZ
SPT2        | 4XYZ
SPT3        | 4XYZ
SPT3        | 9XYZ
SPT4        | 4XYZ
SPT4        | 4XYZ

我只想從上述結果集中返回這些行，因為它們是相同的ProfileType，但是具有兩個不同的ColorCodes

ProfileType | ColorCode
SPT1        | 8XYZ
SPT1        | 1XYZ
SPT3        | 4XYZ
SPT3        | 9XYZ

詢問

SELECT. P.ProfileType, E.ColorCode,
FROM profilegroups AS PG
 INNER JOIN mfg.profiles AS P
         ON PG.id = P.pickgroup
 INNER JOIN exts AS E
         ON E.Profile = P.Profile
        AND E.ProductNumber IN ('XYZ123', 'MX231X')
        AND PG.DoProcess = 1 
        AND P.ProfileType IN ('SPT1','SPT2','SPT3','SPT4','SPTX2','SPT31', 'SPT90');

表

ProfileGroups
    - id
Profiles 
    - Profile 
    - ProfileType 
    - PickGroup
Exts
    - Profile 
    - ColorCode

Profiles和Exts有一個主鍵Profile，它與Profiles不同，后者來自Profiles表。

Answer 1

加入一個子查詢，該子查詢獲取每種配置文件類型的不同顏色代碼的數量，但僅返回具有一個以上顏色代碼的顏色代碼：

SELECT profileType
FROM Exts
GROUP BY profileType
HAVING COUNT(DISTINCT colorCode) > 1

完整的查詢將如下所示：

SELECT. ProfileType, Color,
FROM profilegroups AS PG
 INNER JOIN mfg.profiles AS P
         ON PG.id = P.pickgroup
 INNER JOIN exts AS E
         ON E.ProfileType = P.ProfileType
 INNER JOIN (
    SELECT profile
    FROM Exts
    GROUP BY profile
    HAVING COUNT(DISTINCT colorCode) > 1) M 
        ON M.profile = P.profile
WHERE   E.ProductNumber IN ('XYZ123', 'MX231X')
        AND PG.DoProcess = 1 
        AND P.ProfileType IN ('SPT1','SPT2','SPT3','SPT4','SPTX2','SPT31', 'SPT90')

Answer 2

嘗試這個 ：

select profileType, colorCode
from (select distinct profileType, colorCode from table) a
group by profileType
having count(*) > 1;